Django talk

Django setup on Win7 - can't import some things

2012-02-13T08:35:00.000-08:00

I am trying to get started with Django and having some trouble. I'm
using Django 1.2 to reserve the ability to go to Google's app engine
if I want. I have python 2.7 installed and working on Win7. I
unstalled Django 1.2 using the install script and it copied Django
into the site-packages directory.

I have been working through the tutorial and am just about finished.
However, in the last step, the tutorial uses generic views. When I run
it, I get "cannot import name DetailView". The import command,
straight from the tutorial is "from django.views.generic import
DetailView, ListView".

Early on, I could not execute django-admin.py. I had already installed
PIL and I had read about *.pth files in .../site-packages/*. So I
created a file django.pth. In it I put the single line "django\bin".
After this, django-admin.py could be easily executed.

Do I have to add more lines to django.pth? Is there something else I
missed?

-Bob

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Re: sqlite3 database error

2012-02-13T08:34:00.002-08:00

On Mon, Feb 13, 2012 at 4:01 PM, Dennis Lee Bieber
<wlfraed@ix.netcom.com> wrote:
> On Mon, 13 Feb 2012 01:50:12 -0800 (PST), Marcus Maximus
> <marcus.presich@gmail.com> wrote:
>
>
>> 'NAME': 'C:\Users\Maximus\Desktop\Webseite\Django\sqlite-shell-
>>win32-x86-3071000\test.db', # Or path to database
>
> Is that a typo? "Webseite" and not "Website"?
>

Webseite is German for web-site, so probably not.

Cheers

Tom

Re: django-admin.py startproject doesn't work

2012-02-13T08:34:00.001-08:00

Is "django-admin.py" file in the directory, "Django-1.3.1"??

(If not copy or move the file from in "Django-1.3.1/django/bin/" to
"Django-1.3.1/".)

On 2월13일, 오후4시02분, raddy <raddy.man...@gmail.com> wrote:
> I have windows7 OS and have installed Python27 and Django1.3.1
> I have also set the path in the environment variables to: C:
> \Python27\;C:\Python27\python.exe;C:\Python27\Scripts;C:\Python27\Lib
> \site-packages\django\bin
>
> Commands like python and import django works well but
> when i try creating a new project I get the following error:
>
> C:\Python27\Django-1.3.1>django-admin.py startproject mysite
> 'django-admin.py' is not recognized as an internal or external
> command,
> operable program or batch file.
>
> C:\Python27\Django-1.3.1>
>
> Please help!!!

Model field that links to a page ID, or external URL

2012-02-13T08:09:00.001-08:00

Hi,

In CMS interfaces I generally encounter a problem with URL fields.
In most situations, the following options need to be supported:
- An URL to an external page (Django's URLField can handle that)
- An URL to an internal page (e.g. Django CMS)
- An URL to an other model (e.g. article)

How can I reasonably store this information in a model field?
I would love to store these values as foreign key, as it would allow more querying options.

I've written a solution for this before using a forms.MultiValueField / MultiWidget input,
which did involve the ugly hack of saving the contents as string, using the format:
- http://...external-page/
- pageid://## -- the internal page
- articleid://## -- link to an article.
This works, and did fit in the project deadline.
However, I would like to improve upon this.

Does anyone have a suggestion on how to store the various information properly?

Greetings,
Diederik

Re: django-admin.py startproject doesn't work

2012-02-13T08:01:00.001-08:00

On Sun, 12 Feb 2012 23:02:20 -0800 (PST), raddy <raddy.mandra@gmail.com>
wrote:

>I have windows7 OS and have installed Python27 and Django1.3.1
>I have also set the path in the environment variables to: C:
>\Python27\;C:\Python27\python.exe;C:\Python27\Scripts;C:\Python27\Lib
>\site-packages\django\bin
>
First off -- you can remove tghe python.exe section from the path...
PATH is a list of /directories/ in which executable file are expected to
be found, so there is nothing "in" c:\python27\python.exe to search
(python.exe will be found by the first c:\Python27\ entry.

>Commands like python and import django works well but
>when i try creating a new project I get the following error:
>
>C:\Python27\Django-1.3.1>django-admin.py startproject mysite
>'django-admin.py' is not recognized as an internal or external
>command,
>operable program or batch file.
>

Can you run ANY python script (.py) file by typing its name on the
command line?... Say something that does nothing more than:

print "I'm running"

(test while /in/ the directory that has the file, first)

My suspicion is that you don't have .py defined as a valid "command
file extension" NOR do you have the associations set to run one. What
follows is a listing from Windows Powershell (I had a short cut for it,
but not for the old command shell). Note the last two entries on PATHEXT
-- those make .py and .pyw valid command extensions (supposedly, you
don't even have to type "scriptname.py", only "scriptname", to have the
system find the .py file)[Interesting -- I don't seem to have powershell
scripts on the extension list]

PS C:\Users\Wulfraed> cd env:
PS Env:\> ls

Name Value
---- -----
<snip>
NUMBER_OF_PROCESSORS 8
OS Windows_NT
Path
%SystemRoot%\system32\WindowsPowerShell\v1.0\;C:\GNAT\2011\bin;C:\Python27_64\;C:\Pyt...
PATHEXT .COM;.EXE;.BAT;.CMD;.VBS;.VBE;.JS;.JSE;.WSF;.WSH;.MSC;.py;.pyw
PROCESSOR_ARCHITECTURE AMD64
PROCESSOR_IDENTIFIER Intel64 Family 6 Model 42 Stepping 7,
GenuineIntel
<snip>
PS Env:\>

The OTHER (more likely problem since you entered the extension) is
that you don't have .py files associated with a python interpreter
(note: the "cmd /c" was needed here as they are internal to the old
command shell, not available in powershell itself)

PS Env:\> cmd /c assoc .py
.py=Python.File
PS Env:\> cmd /c ftype Python.File
Python.File="C:\Python27\python.exe" "%1" %*
PS Env:\>

If ASSOC and FTYPE don't show entries, try creating them (may need
to be admin, or they may be stored on a per user basis)...

ftype Python.File="C:\Python27\python.exe" "%1" %*
assoc .py=Python.File

(repeat with pythonw replacing all use of python to set up the "no
console" extension).

{Of course, the last option may just be that, regardless of what you
setup -- django-admin.py is NOT in one of the directories in the search
path}
--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/

Re: sqlite3 database error

2012-02-13T08:01:00.000-08:00

On Mon, 13 Feb 2012 01:50:12 -0800 (PST), Marcus Maximus
<marcus.presich@gmail.com> wrote:

> 'NAME': 'C:\Users\Maximus\Desktop\Webseite\Django\sqlite-shell-
>win32-x86-3071000\test.db', # Or path to database

Is that a typo? "Webseite" and not "Website"?

--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/

Re: Comments Link- How to?

2012-02-13T07:38:00.000-08:00

Oh ok. Just render the comments as usual then use jquery of pure
javascript to hide it by default. Tie the link to the onclick event
such that it triggers the unhiding of the comment div. Simple.

On 2/13/12, coded kid <duffleboi911@gmail.com> wrote:
> Okay. Just like this. <a href="{% url django.comment %}"/> Comment
> Link Name </a>
>
> Where "Comment Link Name" is the name you want to give to your link.
> So when a user click on it, it should show the comment form on the
> same page. I hope you now get my point?
>
> On Feb 13, 1:26 pm, Babatunde Akinyanmi <tundeba...@gmail.com> wrote:
>> Please Rephrase. I don't get the part of "comment link name"
>>
>> On 2/13/12, coded kid <duffleboi...@gmail.com> wrote:
>>
>> > Hi Guys, How can I link to "Django Comment form", so that when a user
>> > clicks on the "Comment Link Name" It will display the Comment Form on
>> > the same page with the post. I hope you get my point? If you do please
>> > answer and if you don't ask me to explain further.
>>
>> > --
>> > You received this message because you are subscribed to the Google
>> > Groups
>> > "Django users" group.
>> > To post to this group, send email to django-users@googlegroups.com.
>> > To unsubscribe from this group, send email to
>> > django-users+unsubscribe@googlegroups.com.
>> > For more options, visit this group at
>> >http://groups.google.com/group/django-users?hl=en.
>>
>> --
>> Sent from my mobile device
>
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Re: Mod_Wsgi + Apache 2.2 + Threads + httplib2

2012-02-13T06:31:00.000-08:00

mod_wsgi doesn't support print, does it? Its usage should raise an
exception.

Re: Comments form customization

2012-02-13T05:50:00.001-08:00

On 02/13/2012 11:12 AM, Fabio Natali wrote:
> http://stackoverflow.com/questions/1456267/django-comments-want-to-remove-user-url-not-expand-the-model-how-to/4766543#4766543

This link worked fine for me. :-)

--
Fabio Natali FNstudio
http://fnstudio.it
fabio_natali@skype

Re: Comments form customization

2012-02-13T05:49:00.000-08:00

On 02/13/2012 11:44 AM:
> Yeah, thanks for the reply. I followed the doc but it's not working
> for me.
[...]

Hi there!

If you have an object my_object passed by your view to your template, I
think you can write:

{% load comments %}
{% get_comment_count for my_object as comment_count %}
{% get_comment_list for my_object as comment_list %}
{% get_comment_form for my_object as form %}

and then you can:

<form action="{% comment_form_target %}" method="post">
{% csrf_token %}
{{ form }}
<tr>
<td colspan="2">
<input type="submit" name="submit" value="Post">
<input type="submit" name="preview" value="Preview">
</td>
</tr>
</form>

Let me know it that's of any help. In case, write me what kind of error
you get. Also, I can pass you my source code so you can have an example.

Cheers, Fabio.

--
Fabio Natali

Re: Comments Link- How to?

2012-02-13T05:24:00.000-08:00

Okay. Just like this. <a href="{% url django.comment %}"/> Comment
Link Name </a>

Where "Comment Link Name" is the name you want to give to your link.
So when a user click on it, it should show the comment form on the
same page. I hope you now get my point?

On Feb 13, 1:26 pm, Babatunde Akinyanmi <tundeba...@gmail.com> wrote:
> Please Rephrase. I don't get the part of "comment link name"
>
> On 2/13/12, coded kid <duffleboi...@gmail.com> wrote:
>
> > Hi Guys, How can I link to "Django Comment form", so that when a user
> > clicks on the "Comment Link Name" It will display the Comment Form on
> > the same page with the post. I hope you get my point? If you do please
> > answer and if you don't ask me to explain further.
>
> > --
> > You received this message because you are subscribed to the Google Groups
> > "Django users" group.
> > To post to this group, send email to django-users@googlegroups.com.
> > To unsubscribe from this group, send email to
> > django-users+unsubscribe@googlegroups.com.
> > For more options, visit this group at
> >http://groups.google.com/group/django-users?hl=en.
>
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> Sent from my mobile device

Re: sqlite3 database error

2012-02-13T05:18:00.001-08:00

Also 'Webseite' in your file path may be misspelled?

Re: error while testing

2012-02-13T05:10:00.003-08:00

Lots of Thanks :)

On 13 February 2012 13:52, Sandro Dutra <hexodin@gmail.com> wrote:

Think it's a name conflict with the model Location, probably it's
registered 2 times in "admin.py" (line 4), or try to change the model
name.

2012/2/13 xina towner <xinatowner@gmail.com>:

> I'm getting this error when I try to do my tests, can anybody help me
> please?
>
> Traceback (most recent call last):
> File "/home/xino/workspace/unnamedapp/accounts/tests.py", line 209, in
> test_request_invitation
> resp = self.client.get('/accounts/invite/request/')
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 439, in get
> response = super(Client, self).get(path, data=data, **extra)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 241, in get
> return self.request(**r)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 381, in request
> response = self.handler(environ)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 84, in __call__
> response = self.get_response(request)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/handlers/base.py",
> line 169, in get_response
> response = self.handle_uncaught_exception(request, resolver,
> sys.exc_info())
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/handlers/base.py",
> line 218, in handle_uncaught_exception
> return callback(request, **param_dict)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/decorators.py",
> line 93, in _wrapped_view
> response = view_func(request, *args, **kwargs)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/views/defaults.py",
> line 31, in server_error
> return http.HttpResponseServerError(t.render(Context({})))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 123, in render
> return self._render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/utils.py",
> line 60, in instrumented_test_render
> return self.nodelist.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 744, in render
> bits.append(self.render_node(node, context))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py",
> line 73, in render_node
> result = node.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/loader_tags.py",
> line 127, in render
> return compiled_parent._render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/utils.py",
> line 60, in instrumented_test_render
> return self.nodelist.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 744, in render
> bits.append(self.render_node(node, context))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py",
> line 73, in render_node
> result = node.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/loader_tags.py",
> line 64, in render
> result = block.nodelist.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 744, in render
> bits.append(self.render_node(node, context))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py",
> line 73, in render_node
> result = node.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/defaulttags.py",
> line 437, in render
> url = reverse(view_name, args=args, kwargs=kwargs,
> current_app=context.current_app)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 391, in reverse
> *args, **kwargs)))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 312, in reverse
> possibilities = self.reverse_dict.getlist(lookup_view)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 229, in _get_reverse_dict
> self._populate()
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 208, in _populate
> for name in pattern.reverse_dict:
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 229, in _get_reverse_dict
> self._populate()
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 197, in _populate
> for pattern in reversed(self.url_patterns):
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 279, in _get_url_patterns
> patterns = getattr(self.urlconf_module, "urlpatterns",
> self.urlconf_module)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 274, in _get_urlconf_module
> self._urlconf_module = import_module(self.urlconf_name)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/importlib.py",
> line 35, in import_module
> __import__(name)
> File "/home/xino/workspace/unnamedapp/urls_web.py", line 6, in <module>
> admin.autodiscover()
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/contrib/admin/__init__.py",
> line 26, in autodiscover
> import_module('%s.admin' % app)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/importlib.py",
> line 35, in import_module
> __import__(name)
> File "/home/xino/workspace/unnamedapp/quests/admin.py", line 4, in
> <module>
> admin.site.register(Location)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/contrib/admin/sites.py",
> line 85, in register
> raise AlreadyRegistered('The model %s is already registered' %
> model.__name__)
> TemplateSyntaxError: Caught AlreadyRegistered while rendering: The model
> Location is already registered
>
>
> Also when I try to run the server and acces with my browser I get this
> error:
>
> AlreadyRegistered at /admin
>
> The model Location is already registered
>
> Does anyone knows how to fix it?
>
> --
> Gràcies,
>
> Rubén
>

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Gràcies,

Rubén

Re: sqlite3 database error

2012-02-13T05:10:00.001-08:00

Try this:

DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3', # Add
'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
'NAME': 'test.db', # Or path to database
file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for
default. Not used with sqlite3.
}

Best Regards,

Stanwin Siow

On Feb 13, 2012, at 9:03 PM, ajohnston wrote:

Try changing the slashes form \ to /

On Feb 13, 4:50 am, Marcus Maximus <marcus.pres...@gmail.com> wrote:
Hey guys,

i am using sqlite3 for my django app. BUT I have problems installing
it. Here are my configs:

DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3', # Add
'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
'NAME': 'C:\Users\Maximus\Desktop\Webseite\Django\sqlite-shell-
win32-x86-3071000\test.db', # Or path to database
file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for
default. Not used with sqlite3.
}

}

I tried this:

from django.db import connection
cursor = connection.cursor()

But I got this error:

Traceback (most recent call last):
File "<console>", line 1, in <module>
File "C:\Python27\lib\site-packages\django\db\backends\__init__.py",
line 250,
in cursor
cursor = self.make_debug_cursor(self._cursor())
File "C:\Python27\lib\site-packages\django\db\backends
\sqlite3\base.py", line
207, in _cursor
self.connection = Database.connect(**kwargs)
OperationalError: unable to open database file

Can sb pls help me?

greetings

Maximus

PS.: I created my sqlite3 file like that:

>sqlite3 test.db
...>
...>
...>);
...>Syntax error
>

Can sb show me a better way to create an empty sqlite3 db file?

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Re: sqlite3 database error

2012-02-13T05:09:00.001-08:00

Sorry. To be clearer, I should have said. In your db file name:

C:\Users\Maximus\Desktop\Webseite\Django\sqlite-shell-win32-
x86-3071000\test.db

try changing the \ to /

See:
https://docs.djangoproject.com/en/dev/ref/settings/#name

Re: sqlite3 database error

2012-02-13T05:03:00.001-08:00

Try changing the slashes form \ to /

On Feb 13, 4:50 am, Marcus Maximus <marcus.pres...@gmail.com> wrote:
> Hey guys,
>
> i am using sqlite3 for my django app. BUT I have problems installing
> it. Here are my configs:
>
> DATABASES = {
> 'default': {
> 'ENGINE': 'django.db.backends.sqlite3', # Add
> 'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
> 'NAME': 'C:\Users\Maximus\Desktop\Webseite\Django\sqlite-shell-
> win32-x86-3071000\test.db', # Or path to database
> file if using sqlite3.
> 'USER': '', # Not used with sqlite3.
> 'PASSWORD': '', # Not used with sqlite3.
> 'HOST': '', # Set to empty string for
> localhost. Not used with sqlite3.
> 'PORT': '', # Set to empty string for
> default. Not used with sqlite3.
> }
>
> }
>
> I tried this:
>
> >>> from django.db import connection
> >>> cursor = connection.cursor()
>
> But I got this error:
>
> Traceback (most recent call last):
> File "<console>", line 1, in <module>
> File "C:\Python27\lib\site-packages\django\db\backends\__init__.py",
> line 250,
> in cursor
> cursor = self.make_debug_cursor(self._cursor())
> File "C:\Python27\lib\site-packages\django\db\backends
> \sqlite3\base.py", line
> 207, in _cursor
> self.connection = Database.connect(**kwargs)
> OperationalError: unable to open database file
>
> Can sb pls help me?
>
> greetings
>
> Maximus
>
> PS.: I created my sqlite3 file like that:
>
> >sqlite3 test.db
> ...>
> ...>
> ...>);
> ...>Syntax error
> >
>
> Can sb show me a better way to create an empty sqlite3 db file?

Re: error while testing

2012-02-13T04:52:00.000-08:00

Think it's a name conflict with the model Location, probably it's
registered 2 times in "admin.py" (line 4), or try to change the model
name.

2012/2/13 xina towner <xinatowner@gmail.com>:
> I'm getting this error when I try to do my tests, can anybody help me
> please?
>
> Traceback (most recent call last):
> File "/home/xino/workspace/unnamedapp/accounts/tests.py", line 209, in
> test_request_invitation
> resp = self.client.get('/accounts/invite/request/')
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 439, in get
> response = super(Client, self).get(path, data=data, **extra)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 241, in get
> return self.request(**r)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 381, in request
> response = self.handler(environ)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py",
> line 84, in __call__
> response = self.get_response(request)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/handlers/base.py",
> line 169, in get_response
> response = self.handle_uncaught_exception(request, resolver,
> sys.exc_info())
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/handlers/base.py",
> line 218, in handle_uncaught_exception
> return callback(request, **param_dict)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/decorators.py",
> line 93, in _wrapped_view
> response = view_func(request, *args, **kwargs)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/views/defaults.py",
> line 31, in server_error
> return http.HttpResponseServerError(t.render(Context({})))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 123, in render
> return self._render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/utils.py",
> line 60, in instrumented_test_render
> return self.nodelist.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 744, in render
> bits.append(self.render_node(node, context))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py",
> line 73, in render_node
> result = node.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/loader_tags.py",
> line 127, in render
> return compiled_parent._render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/utils.py",
> line 60, in instrumented_test_render
> return self.nodelist.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 744, in render
> bits.append(self.render_node(node, context))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py",
> line 73, in render_node
> result = node.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/loader_tags.py",
> line 64, in render
> result = block.nodelist.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py",
> line 744, in render
> bits.append(self.render_node(node, context))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py",
> line 73, in render_node
> result = node.render(context)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/defaulttags.py",
> line 437, in render
> url = reverse(view_name, args=args, kwargs=kwargs,
> current_app=context.current_app)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 391, in reverse
> *args, **kwargs)))
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 312, in reverse
> possibilities = self.reverse_dict.getlist(lookup_view)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 229, in _get_reverse_dict
> self._populate()
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 208, in _populate
> for name in pattern.reverse_dict:
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 229, in _get_reverse_dict
> self._populate()
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 197, in _populate
> for pattern in reversed(self.url_patterns):
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 279, in _get_url_patterns
> patterns = getattr(self.urlconf_module, "urlpatterns",
> self.urlconf_module)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py",
> line 274, in _get_urlconf_module
> self._urlconf_module = import_module(self.urlconf_name)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/importlib.py",
> line 35, in import_module
> __import__(name)
> File "/home/xino/workspace/unnamedapp/urls_web.py", line 6, in <module>
> admin.autodiscover()
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/contrib/admin/__init__.py",
> line 26, in autodiscover
> import_module('%s.admin' % app)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/importlib.py",
> line 35, in import_module
> __import__(name)
> File "/home/xino/workspace/unnamedapp/quests/admin.py", line 4, in
> <module>
> admin.site.register(Location)
> File
> "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/contrib/admin/sites.py",
> line 85, in register
> raise AlreadyRegistered('The model %s is already registered' %
> model.__name__)
> TemplateSyntaxError: Caught AlreadyRegistered while rendering: The model
> Location is already registered
>
>
> Also when I try to run the server and acces with my browser I get this
> error:
>
> AlreadyRegistered at /admin
>
> The model Location is already registered
>
> Does anyone knows how to fix it?
>
> --
> Gràcies,
>
> Rubén
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To post to this group, send email to django-users@googlegroups.com.
> To unsubscribe from this group, send email to
> django-users+unsubscribe@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/django-users?hl=en.

Re: sqlite3 database error

2012-02-13T04:35:00.001-08:00

After specifying the path to where you want your sqlite database to be
i.e db name setting, after your syncdb, the database will be created
automatically if it doesn't already exist in the path you stated.

On 2/13/12, Marcus Maximus <marcus.presich@gmail.com> wrote:
> Hey guys,
>
> i am using sqlite3 for my django app. BUT I have problems installing
> it. Here are my configs:
>
> DATABASES = {
> 'default': {
> 'ENGINE': 'django.db.backends.sqlite3', # Add
> 'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
> 'NAME': 'C:\Users\Maximus\Desktop\Webseite\Django\sqlite-shell-
> win32-x86-3071000\test.db', # Or path to database
> file if using sqlite3.
> 'USER': '', # Not used with sqlite3.
> 'PASSWORD': '', # Not used with sqlite3.
> 'HOST': '', # Set to empty string for
> localhost. Not used with sqlite3.
> 'PORT': '', # Set to empty string for
> default. Not used with sqlite3.
> }
> }
>
> I tried this:
>
>>>> from django.db import connection
>>>> cursor = connection.cursor()
>
> But I got this error:
>
> Traceback (most recent call last):
> File "<console>", line 1, in <module>
> File "C:\Python27\lib\site-packages\django\db\backends\__init__.py",
> line 250,
> in cursor
> cursor = self.make_debug_cursor(self._cursor())
> File "C:\Python27\lib\site-packages\django\db\backends
> \sqlite3\base.py", line
> 207, in _cursor
> self.connection = Database.connect(**kwargs)
> OperationalError: unable to open database file
>
> Can sb pls help me?
>
> greetings
>
> Maximus
>
> PS.: I created my sqlite3 file like that:
>
> >sqlite3 test.db
> ...>
> ...>
> ...>);
> ...>Syntax error
> >
>
> Can sb show me a better way to create an empty sqlite3 db file?
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To post to this group, send email to django-users@googlegroups.com.
> To unsubscribe from this group, send email to
> django-users+unsubscribe@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/django-users?hl=en.
>
>

--
Sent from my mobile device

Re: Comments Link- How to?

2012-02-13T04:26:00.000-08:00

Please Rephrase. I don't get the part of "comment link name"

On 2/13/12, coded kid <duffleboi911@gmail.com> wrote:
> Hi Guys, How can I link to "Django Comment form", so that when a user
> clicks on the "Comment Link Name" It will display the Comment Form on
> the same page with the post. I hope you get my point? If you do please
> answer and if you don't ask me to explain further.
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To post to this group, send email to django-users@googlegroups.com.
> To unsubscribe from this group, send email to
> django-users+unsubscribe@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/django-users?hl=en.
>
>

--
Sent from my mobile device

Re: complete for dropdown box in admin

2012-02-13T04:07:00.001-08:00

On Mon, 2012-02-13 at 17:15 +0530, Anoop Thomas Mathew wrote:
> http://harvesthq.github.com/chosen/
> Hope this helps.
>
>

looks just like what I wanted. And this helps too:

http://bradmontgomery.net/blog/chosenjs-in-the-django-admin/
--
regards
Kenneth Gonsalves

Comments Link- How to?

2012-02-13T04:04:00.000-08:00

Hi Guys, How can I link to "Django Comment form", so that when a user
clicks on the "Comment Link Name" It will display the Comment Form on
the same page with the post. I hope you get my point? If you do please
answer and if you don't ask me to explain further.

django admin templates: filter
hides table contents

2012-02-13T04:02:00.000-08:00

Hi,

I wanted to know whether anybody modified the django admin templates such,
that the filter div could be hidden.

At the moment the <div> containing the filters may hide the
contents of the table.

As I can imagine, that I'm not the only one who might have large tables
and doesn't like, that part of the table data is hidden behind these
filters I wanted to know whether anybody changed the templates / style
sheets / javascript such, that it is possible to
show / hide the filter window (similiar to how it is done for the
django debug tool bar.

Usage of jquery for showing / hiding is no wroblem as I juse jquery
already for other pages.

Thanks in advance for your answers.

error

2012-02-13T03:51:00.001-08:00

Hi, I get this message when I try to acces to the admin page:

AlreadyRegistered at /admin

  The model Location is already registered

does anybody know which is the problem?

--
Gràcies,

Rubén

Re: complete for dropdown box in admin

2012-02-13T03:45:00.000-08:00

Hi,

http://harvesthq.github.com/chosen/
Hope this helps.

Thanks,
Anoop Thomas Mathew

atm
___
Life is short, Live it hard.

On 13 February 2012 12:17, kenneth gonsalves <lawgon@thenilgiris.com> wrote:

hi,

I need a widget in admin to autoselect (I do not know what it is called)
a foreign key - that is if I type 'f' it goes to the first occurrence of
'f' and so on. I hope I am clear.
--
regards
Kenneth Gonsalves

--
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To post to this group, send email to django-users@googlegroups.com.
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error while testing

2012-02-13T03:12:00.000-08:00

I'm getting this error when I try to do my tests, can anybody help me please?

Traceback (most recent call last):

File "/home/xino/workspace/unnamedapp/accounts/tests.py", line 209, in test_request_invitation

resp = self.client.get('/accounts/invite/request/')

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py", line 439, in get

response = super(Client, self).get(path, data=data, **extra)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py", line 241, in get

return self.request(**r)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py", line 381, in request

response = self.handler(environ)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/client.py", line 84, in __call__

response = self.get_response(request)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 169, in get_response

response = self.handle_uncaught_exception(request, resolver, sys.exc_info())

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 218, in handle_uncaught_exception

return callback(request, **param_dict)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/decorators.py", line 93, in _wrapped_view

response = view_func(request, *args, **kwargs)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/views/defaults.py", line 31, in server_error

return http.HttpResponseServerError(t.render(Context({})))

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py", line 123, in render

return self._render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/utils.py", line 60, in instrumented_test_render

return self.nodelist.render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py", line 744, in render

bits.append(self.render_node(node, context))

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py", line 73, in render_node

result = node.render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/loader_tags.py", line 127, in render

return compiled_parent._render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/test/utils.py", line 60, in instrumented_test_render

return self.nodelist.render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py", line 744, in render

bits.append(self.render_node(node, context))

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py", line 73, in render_node

result = node.render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/loader_tags.py", line 64, in render

result = block.nodelist.render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/base.py", line 744, in render

bits.append(self.render_node(node, context))

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/debug.py", line 73, in render_node

result = node.render(context)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/template/defaulttags.py", line 437, in render

url = reverse(view_name, args=args, kwargs=kwargs, current_app=context.current_app)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 391, in reverse

*args, **kwargs)))

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 312, in reverse

possibilities = self.reverse_dict.getlist(lookup_view)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 229, in _get_reverse_dict

self._populate()

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 208, in _populate

for name in pattern.reverse_dict:

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 229, in _get_reverse_dict

self._populate()

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 197, in _populate

for pattern in reversed(self.url_patterns):

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 279, in _get_url_patterns

patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/core/urlresolvers.py", line 274, in _get_urlconf_module

self._urlconf_module = import_module(self.urlconf_name)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module

__import__(name)

File "/home/xino/workspace/unnamedapp/urls_web.py", line 6, in <module>

admin.autodiscover()

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/contrib/admin/__init__.py", line 26, in autodiscover

import_module('%s.admin' % app)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module

__import__(name)

File "/home/xino/workspace/unnamedapp/quests/admin.py", line 4, in <module>

admin.site.register(Location)

File "/home/xino/.virtualenvs/xinovirtualenv/local/lib/python2.7/site-packages/django/contrib/admin/sites.py", line 85, in register

raise AlreadyRegistered('The model %s is already registered' % model.__name__)

TemplateSyntaxError: Caught AlreadyRegistered while rendering: The model Location is already registered

Also when I try to run the server and acces with my browser I get this error:

AlreadyRegistered at /admin

  The model Location is already registered

Does anyone knows how to fix it?

--
Gràcies,

Rubén

Re: Admin inline for inherited model cant find pointer to parent model

2012-02-13T02:44:00.000-08:00

Looking more into this,

my parent model has a primary key field named 'code'. The inline forms
do show the 'code' field for the child model instances, and the data
is in the formset's querydict:
QueryDict <... u'childmodel_set-0-code': [u'...'] ...>

However the table column name for the one-to-one relationship between
parent and child is called 'parendmodel__ptr__id', and the admin is
looking for 'childmodel_set-0-parentmodel_ptr' in the formset data.
Why?

On Mon, Feb 13, 2012 at 10:43 AM, Demetrio Girardi
<demetrio.girardi@gmail.com> wrote:
> I have a child model that I wish edit inline in the admin site. When
> trying to save edits I get a MultiValueDictKeyError:
>
> "Key 'childmodel_set-0-parentmodel_ptr' not found in <QueryDict: ..>"
>
> It seems to me the admin is trying to get the reference to the parent
> model from the form data. How can I fix this? Do I need a custom form?

Re: Comments form customization

2012-02-13T02:33:00.000-08:00

Hey Fabio,
How do you get your comment form to display? Been fighting with this
for the past 5hrs. Please any idea? Thanks.

On Feb 13, 11:12 am, Fabio Natali <fa...@fnstudio.it> wrote:
> On 02/13/2012 10:52 AM, Vovk Donets wrote:
>
> > It's not really great solution, but maybe it will give you a hint: you
> > can add/remove fileds to the form on the fly. And for not logged in
> > users show all fields, but for authenticated only subset of the all form
> > fields.
>
> Ehi Vladimir, thank you for your quick reply!
>
> I found a couple of interesting links.
>
> http://mitchfournier.com/2010/08/12/customizing-django-comments-remov...http://stackoverflow.com/questions/1456267/django-comments-want-to-re...
>
> The first deals with writing your own comment templates, so to remove
> unnecessary fields (name, url, email).
>
> The latter deals with writing your own custom comment form, no need to
> hack template stuff. This looks nicer to me, I think I'll try it first.
>
> Vladimir, is that the approach you meant?
>
> I am still not sure this is the best solution for me. So, those of you
> who are listening, if you have any further advice/hint, don't hesitate
> to email me! :-)
>
> Cheers, Fabio.
>
> --
> Fabio Natali

Re: Comments form customization

2012-02-13T02:12:00.001-08:00

On 02/13/2012 10:52 AM, Vovk Donets wrote:
> It's not really great solution, but maybe it will give you a hint: you
> can add/remove fileds to the form on the fly. And for not logged in
> users show all fields, but for authenticated only subset of the all form
> fields.

Ehi Vladimir, thank you for your quick reply!

I found a couple of interesting links.

http://mitchfournier.com/2010/08/12/customizing-django-comments-remove-unwanted-fields/
http://stackoverflow.com/questions/1456267/django-comments-want-to-remove-user-url-not-expand-the-model-how-to/4766543#4766543

The first deals with writing your own comment templates, so to remove
unnecessary fields (name, url, email).

The latter deals with writing your own custom comment form, no need to
hack template stuff. This looks nicer to me, I think I'll try it first.

Vladimir, is that the approach you meant?

I am still not sure this is the best solution for me. So, those of you
who are listening, if you have any further advice/hint, don't hesitate
to email me! :-)

Cheers, Fabio.

--
Fabio Natali

Re: Comments form customization

2012-02-13T01:52:00.000-08:00

It's not really great solution, but maybe it will give you a hint: you can add/remove fileds to the form on the fly. And for not logged in users show all fields, but for authenticated only subset of the all form fields.

2012/2/13 Fabio Natali <fabio@fnstudio.it>

Hi everybody,

I am using comments app from contrib in Django 1.3.

In my website I let only authenticated users to leave a comment so I'd like to get rid of those "name", "email" and "url" fields that come with the standard comment form. Indeed, I already know the name and email of current logged user, there's no need for the user to submit his/her name and email again.

So, I'd just like a FK field to the user that left the comment. More of that, I would like that field to be automatically populated while the user submit the comment.

Could you give me some hints for such customization?

Thank you very much,
Fabio.

--
Fabio Natali

--
Vovk Donets
python developer

sqlite3 database error

2012-02-13T01:50:00.000-08:00

Hey guys,

i am using sqlite3 for my django app. BUT I have problems installing
it. Here are my configs:

DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3', # Add
'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
'NAME': 'C:\Users\Maximus\Desktop\Webseite\Django\sqlite-shell-
win32-x86-3071000\test.db', # Or path to database
file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for
default. Not used with sqlite3.
}
}

I tried this:

>>> from django.db import connection
>>> cursor = connection.cursor()

But I got this error:

Traceback (most recent call last):
File "<console>", line 1, in <module>
File "C:\Python27\lib\site-packages\django\db\backends\__init__.py",
line 250,
in cursor
cursor = self.make_debug_cursor(self._cursor())
File "C:\Python27\lib\site-packages\django\db\backends
\sqlite3\base.py", line
207, in _cursor
self.connection = Database.connect(**kwargs)
OperationalError: unable to open database file

Can sb pls help me?

greetings

Maximus

PS.: I created my sqlite3 file like that:

>sqlite3 test.db
...>
...>
...>);
...>Syntax error
>

Can sb show me a better way to create an empty sqlite3 db file?

Admin inline for inherited model cant find pointer to parent model

2012-02-13T01:43:00.001-08:00

I have a child model that I wish edit inline in the admin site. When
trying to save edits I get a MultiValueDictKeyError:

"Key 'childmodel_set-0-parentmodel_ptr' not found in <QueryDict: ..>"

It seems to me the admin is trying to get the reference to the parent
model from the form data. How can I fix this? Do I need a custom form?

Comments form customization

2012-02-13T01:43:00.000-08:00

Hi everybody,

I am using comments app from contrib in Django 1.3.

In my website I let only authenticated users to leave a comment so I'd
like to get rid of those "name", "email" and "url" fields that come with
the standard comment form. Indeed, I already know the name and email of
current logged user, there's no need for the user to submit his/her name
and email again.

So, I'd just like a FK field to the user that left the comment. More of
that, I would like that field to be automatically populated while the
user submit the comment.

Could you give me some hints for such customization?

Thank you very much,
Fabio.

--
Fabio Natali

Comment post not allowed (400)

2012-02-13T01:28:00.000-08:00

Hey guys, when I include the django comments form in the template I
want to use it, After visting the page, I can only see "POST" and
"PREVIEW" button and the form itself is not showing. So I clicked on
the 'POST" button to see what's next.

After clicking it, I get this:

Comment post not allowed (400)
Why: Missing content_type or object_pk field.

The comment you tried to post to this view wasn't saved because
something tampered with the security information in the comment form.
The message above should explain the problem, or you can check the
comment documentation for more help.

You're seeing this error because you have DEBUG = True in your Django
settings file. Change that to False, and Django will display a
standard 400 error page.

Django Documents aint helping in this case. Please What I'm I missing?
below is the codes in my form.html

{% load comments i18n %}
<form action="{% comment_form_target %}" method="post">{% csrf_token
%}
{% if next %}<div><input type="hidden" name="next"
value="{{ next }}" /></div>{% endif %}
{% for field in form %}
{% if field.is_hidden %}
<div>{{ field }}</div>
{% else %}
{% if field.errors %}{{ field.errors }}{% endif %}
<p
{% if field.errors %} class="error"{% endif %}
{% ifequal field.name "honeypot" %} style="display:none;"{%
endifequal %}>
{{ field.label_tag }} {{ field }}
</p>
{% endif %}
{% endfor %}
<p class="submit">
<input type="submit" name="post" class="submit-post" value="{%
trans "Post" %}" />
{# <input type="submit" name="preview" class="submit-preview"
value="{% trans "Preview" %}" /> #}
</p>
</form>

Database test error

2012-02-13T01:09:00.000-08:00

Hello, I still get this error:

Traceback (most recent call last):

File "manage.py", line 14, in <module>

execute_manager(settings)

File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 438, in execute_manager

utility.execute()

File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 379, in execute

self.fetch_command(subcommand).run_from_argv(self.argv)

File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 191, in run_from_argv

self.execute(*args, **options.__dict__)

File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 220, in execute

output = self.handle(*args, **options)

File "/usr/local/lib/python2.7/dist-packages/south/management/commands/test.py", line 8, in handle

super(Command, self).handle(*args, **kwargs)

File "/usr/local/lib/python2.7/dist-packages/django/core/management/commands/test.py", line 37, in handle

failures = test_runner.run_tests(test_labels)

File "/usr/local/lib/python2.7/dist-packages/django/test/simple.py", line 358, in run_tests

suite = self.build_suite(test_labels, extra_tests)

File "/usr/local/lib/python2.7/dist-packages/django/test/simple.py", line 248, in build_suite

suite.addTest(build_suite(app))

File "/usr/local/lib/python2.7/dist-packages/django/test/simple.py", line 77, in build_suite

test_module = get_tests(app_module)

File "/usr/local/lib/python2.7/dist-packages/django/test/simple.py", line 35, in get_tests

test_module = __import__('.'.join(app_path + [TEST_MODULE]), {}, {}, TEST_MODULE)

File "/home/xino/workspace/unnamedapp/quests/tests.py", line 9, in <module>

from views_web import *

File "/home/xino/workspace/unnamedapp/quests/views_web.py", line 6, in <module>

from quests import views_generic

File "/home/xino/workspace/unnamedapp/quests/views_generic.py", line 3, in <module>

from quests.forms import *

File "/home/xino/workspace/unnamedapp/quests/forms.py", line 487, in <module>

class SearchQuestForm(forms.Form):

File "/home/xino/workspace/unnamedapp/quests/forms.py", line 494, in SearchQuestForm

[CATEGORY_CHOICES.append((c.id, c.name)) for c in Category.objects.all()]

File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 107, in _result_iter

self._fill_cache()

File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 772, in _fill_cache

self._result_cache.append(self._iter.next())

File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 273, in iterator

for row in compiler.results_iter():

File "/usr/local/lib/python2.7/dist-packages/django/db/models/sql/compiler.py", line 680, in results_iter

for rows in self.execute_sql(MULTI):

File "/usr/local/lib/python2.7/dist-packages/django/db/models/sql/compiler.py", line 735, in execute_sql

cursor.execute(sql, params)

File "/usr/local/lib/python2.7/dist-packages/django/db/backends/sqlite3/base.py", line 234, in execute

return Database.Cursor.execute(self, query, params)

django.db.utils.DatabaseError: no such table: quests_category

The problem es the order that django creates the tables in the database. Can I change this?

--
Gràcies,

Rubén

Re: same code runs on two machines and barfs on the third [solved]

2012-02-12T23:53:00.000-08:00

On Wed, 2012-02-08 at 12:45 +0530, kenneth gonsalves wrote:
> On Tue, 2012-02-07 at 19:29 +1100, Mike Dewhirst wrote:
> > On 7/02/2012 6:14pm, kenneth gonsalves wrote:
> > > On Tue, 2012-02-07 at 08:06 +0100, Babatunde Akinyanmi wrote:
> > >> Perhaps you made a change to a model and forgot to syncdb on your
> > >> Fedora 15 machine.....
> > >
> >
> > When you have eliminated all the possibilities what remains must be
> > the
> > problem :)
> >
> > The trick is to confirm your assumptions one by one.
>
> code: all three machines are running code pulled from the same repo.
> django version: all three are on r 17461
> database: the table structure on all three is identical. (in fact two
> machines have the same data also). Postgresql versions differ, but
> this
> is a django error - not a database error.
> The offending line of code worked fine on the F15 machine when it was
> running F14
> Altitude: two of the machines are at 7200 feet above sea level, but
> the
> offending machine is at 3400 feet.

I finally deleted the whole django-trunk and made a fresh svn checkout.
Then it works. Must have been some stale .pyc file or some file got
corrupted.
--
regards
Kenneth Gonsalves

django-admin.py startproject doesn't work

2012-02-12T23:02:00.001-08:00

I have windows7 OS and have installed Python27 and Django1.3.1
I have also set the path in the environment variables to: C:
\Python27\;C:\Python27\python.exe;C:\Python27\Scripts;C:\Python27\Lib
\site-packages\django\bin

Commands like python and import django works well but
when i try creating a new project I get the following error:

C:\Python27\Django-1.3.1>django-admin.py startproject mysite
'django-admin.py' is not recognized as an internal or external
command,
operable program or batch file.

C:\Python27\Django-1.3.1>

Please help!!!

Re: Django Comments Form not Displaying

2012-02-12T22:54:00.000-08:00

Thanks guys. @matias I tried your solution, and the post button
appeared. After clicking on it, I get 'COMMENT POST NOT ALLOWED (404)'
Please whats wrong?

On Feb 12, 4:37 pm, Matías Aguirre <matiasagui...@gmail.com> wrote:
> Excerpts from Michael P. Soulier's message of 2012-02-12 14:16:26 -0200:
>
>
>
>
>
> > On 12/02/12 coded kid said:
>
> > > Below is the codes in my comments/form.html
> > > {% load comments i18n %}
> > > <form action="{% comment_form_target %}" method="post">{% csrf_token
> > > %}
> > > {% if next %}<div><input type="hidden" name="next"
> > > value="{{ next }}" /></div>{% endif %}
> > > {% for field in form %}
> > > {% if field.is_hidden %}
> > > <div>{{ field }}</div>
> > > {% else %}
> > > {% if field.errors %}{{ field.errors }}{% endif %}
> > > <p
> > > {% if field.errors %} class="error"{% endif %}
> > > {% ifequal field.name "honeypot" %} style="display:none;"{%
> > > endifequal %}>
> > > {{ field.label_tag }} {{ field }}
> > > </p>
> > > {% endif %}
> > > {% endfor %}
> > > <p class="submit">
> > > <input type="submit" name="post" class="submit-post" value="{%
> > > trans "Post" %}" />
> > > <input type="submit" name="preview" class="submit-preview"
> > > value="{% trans "Preview" %}" />
> > > </p>
> > > </form>
>
> > You have conditionals on all output. If you're seeing a blank page, perhaps
> > those conditionals are all false. Put in some unconditional content and see if
> > it renders, and then start testing your conditionals.
>
> "/comments/post" is decorated by require_POST, that means that POST is the only
> method allowed to access that view, check your response, you should be getting
> a 405 response.
>
> You should include the form in the page you want it to display, let's say
> a blog post page, but if you want the form on a single page, then you need to
> define a different URL and view to render the template.
>
> Regards,
> Matías
> --
> Matías Aguirre (matiasagui...@gmail.com)

complete for dropdown box in admin

2012-02-12T22:47:00.001-08:00

hi,

I need a widget in admin to autoselect (I do not know what it is called)
a foreign key - that is if I type 'f' it goes to the first occurrence of
'f' and so on. I hope I am clear.
--
regards
Kenneth Gonsalves

Re: Thread timeout

2012-02-12T18:37:00.000-08:00

On Sun, 12 Feb 2012 18:30:41 -0300, Phyllipe Medeiros
<phyllipecesar@gmail.com> wrote:

>Then I have a view that calls Teste().start(), the message that I receive
>on error log is only "BEGIN".
>But if I do no use a thread, the "error log" will work correctly "Begin,
>PASSED SLEEP" and "OUT".
>I think it is something related to Apache2/Mod_wsgi or even permissions in
>my system, because if run it with sudo using runserver it will work
>perfectly.
>In my house it works perfectly too.

And what happens if, in your view, you replace

Teste().start()

with

t = Teste()
t.start()
t.join()

"runserver" is a continuously running Python program, as I recall
and your application essentially runs within it. Apache/mod_wsgi (based
on http://code.google.com/p/modwsgi/ ) apparently can be configured in
two modes. I suspect one of those modes is seeing the application
"shutting down" before it captures the output (Or... it receives the
"begin" output, and then nothing for a period of time, and may presume
the process is hung or has no further output). Using .join() would, at
the least, keep the main process from initiating shutdown until the
thread completes (this could be an alternative hypothesis -- the main
process starts shutdown, closing stdout /before/ waiting for the thread
to complete)
--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/

Re: Problem with encoding in unit tests

2012-02-12T15:54:00.000-08:00

How did you get the name into your fixtures? Did you type it in
manually, or enter it in Django admin and then use dumpdata?

It looks like the value in your fixtures got its encoding mangled. It
should work properly if the unicode is correct in your database and you
use manage.py dumpdata to dump it to json.

If none of this helps, please post the relevant portion of your fixtures.

Django Gigs - Why so few gigs?

2012-02-12T14:51:00.000-08:00

A year or so (may be more) back when I looked at Django Gigs and there
were quite a lot of gigs( I mean in 100s). After a while I checked
again today just to see how the market is doing and I see very few
jobs on django gigs.

What happened, what changed?

Problem with encoding in unit tests

2012-02-12T14:44:00.000-08:00

Hi everyone,

I am having some problems with unit tests in Django.

If I run this code in the django shell, I got the expected result:
In [2]: actividades = ActividadExtracurricular.objects.order_by("id")

In [3]: print (actividades[1].nombre == u"Soñar despierto",
actividades[1].nombre)
Out[3]: (True, u'So\xc3\xb1ar despierto')

But when I put the same code in the tests.py file, the following
happens:
Creating test database for alias 'default'...
(False, u'So\xc3\xb1ar despierto')

Does anyone know how to solve this problem?

Thanks in advance =),
David Gómez.

Re: [modwsgi] Thread timeout

2012-02-12T14:37:00.001-08:00

On 13 February 2012 08:30, Phyllipe Medeiros <phyllipecesar@gmail.com> wrote:
> I have made this class:
> "class Teste(Thread):
> def __init__(self):
> Thread.__init__(self)
> def run(self):
> try:
> print "Begin"
> from httplib2 import Http
> import time
> time.sleep(20)
> print "PASSED SLEEP"
> response, content = Http().request("http://www.spoj.pl")
> print "OUT"
> except:

Within the except add:

import sys
import traceback
traceback.print_exception(*sys.exc_info())

If you aren't going to re raise the exception, then how else are you
going to know what the actual problem is.

Graham

> print "EXCEPTION :("
> "
> Then I have a view that calls Teste().start(), the message that I receive on
> error log is only "BEGIN".
> But if I do no use a thread, the "error log" will work correctly "Begin,
> PASSED SLEEP" and "OUT".
> I think it is something related to Apache2/Mod_wsgi or even permissions in
> my system, because if run it with sudo using runserver it will work
> perfectly.
> In my house it works perfectly too.
>
>
>
> --
> You received this message because you are subscribed to the Google Groups
> "modwsgi" group.
> To post to this group, send email to modwsgi@googlegroups.com.
> To unsubscribe from this group, send email to
> modwsgi+unsubscribe@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/modwsgi?hl=en.

Thread timeout

2012-02-12T13:30:00.000-08:00

I have made this class:

"class Teste(Thread):

def __init__(self):

Thread.__init__(self)

def run(self):

try:

print "Begin"

from httplib2 import Http

import time

time.sleep(20)

print "PASSED SLEEP"

response, content = Http().request("http://www.spoj.pl")

print "OUT"

except:

print "EXCEPTION :("

Then I have a view that calls Teste().start(), the message that I receive on error log is only "BEGIN".

But if I do no use a thread, the "error log" will work correctly "Begin, PASSED SLEEP" and "OUT".

I think it is something related to Apache2/Mod_wsgi or even permissions in my system, because if run it with sudo using runserver it will work perfectly.

In my house it works perfectly too.

Re: accessing foreign key value in template select related

2012-02-12T13:25:00.001-08:00

sorry left something out which was actually causing the lookup to
fail. I have overidden the Select that gets given by default with a
foreign key to a CharField for ajax autocomple.
So i guess is how to i get the relationship lookup to work with the
select changed to a CharField?

class ProfileEditForm(ModelForm):
city_id = forms.CharField(max_length=200,required=False)

class Meta:
model = UserProfile

On Feb 12, 8:32 pm, richard <pullenjenn...@gmail.com> wrote:
> Hi i have a UserProfile that has a city_id as a foreign key to cities
> table. when i use {{ profile_edit_form.city_id}} in the template i get
> the id of the city that is stored in my userprofile showing as the
> value instead of the city name. Would the select related fix this
> issue and lookup the city name form the city table based on the city
> id in the userprofile? ive tried useing select related on my queries
> but it gives me an error saying userprofile has no select related. any
> help would be much appreciated.
>
> code
> models.py
> #this class was genrated using inspectdb
> class Cities(models.Model):
> id = models.IntegerField(primary_key=True, db_column='ID') # Field
> name made lowercase.
> country = models.CharField(unique=True, max_length=6)
> region = models.CharField(unique=True, max_length=9)
> url = models.CharField(max_length=150)
> name = models.CharField(unique=True, max_length=150)
> latitude = models.FloatField()
> longitude = models.FloatField()
> class Meta:
> db_table = u'cities
>
> class UserProfile(models.Model):
> user = models.OneToOneField(User)
> city_id =
> models.ForeignKey(Cities,blank=True,db_column='city_id')#tried adding
> this too related_name='cities'
>
> forms.py
> class ProfileEditForm(ModelForm):
> class Meta:
> model = UserProfile
>
> views.py
>
> def edit(request):
> c = {}
> c.update(csrf(request))
> profile_edit_form =
> ProfileEditForm(instance=request.user.get_profile()) #tried
> adding .select_related() here
> if request.method == "POST":
>
> profile_edit_form =
> ProfileEditForm(request.POST,request.FILES,instance=request.user.get_profile())
> if profile_edit_form.is_valid():
> p = profile_edit_form.save()
> city = Cities.objects.get(pk=request.POST['cid'])
> p.city_id = city
> p.save()
>
> c['profile_edit_form'] = profile_edit_form
> return render_to_response('profile/edit.html', c,
> context_instance=RequestContext(request))
>
> template
>
> in my template {{ profile_edit_form }} #shows the city id not the
> actual city name refered to by the id ?
>
> thanks

accessing foreign key value in template select related

2012-02-12T12:32:00.000-08:00

Hi i have a UserProfile that has a city_id as a foreign key to cities
table. when i use {{ profile_edit_form.city_id}} in the template i get
the id of the city that is stored in my userprofile showing as the
value instead of the city name. Would the select related fix this
issue and lookup the city name form the city table based on the city
id in the userprofile? ive tried useing select related on my queries
but it gives me an error saying userprofile has no select related. any
help would be much appreciated.

code
models.py
#this class was genrated using inspectdb
class Cities(models.Model):
id = models.IntegerField(primary_key=True, db_column='ID') # Field
name made lowercase.
country = models.CharField(unique=True, max_length=6)
region = models.CharField(unique=True, max_length=9)
url = models.CharField(max_length=150)
name = models.CharField(unique=True, max_length=150)
latitude = models.FloatField()
longitude = models.FloatField()
class Meta:
db_table = u'cities

class UserProfile(models.Model):
user = models.OneToOneField(User)
city_id =
models.ForeignKey(Cities,blank=True,db_column='city_id')#tried adding
this too related_name='cities'

forms.py
class ProfileEditForm(ModelForm):
class Meta:
model = UserProfile

views.py

def edit(request):
c = {}
c.update(csrf(request))
profile_edit_form =
ProfileEditForm(instance=request.user.get_profile()) #tried
adding .select_related() here
if request.method == "POST":

profile_edit_form =
ProfileEditForm(request.POST,request.FILES,instance=request.user.get_profile())
if profile_edit_form.is_valid():
p = profile_edit_form.save()
city = Cities.objects.get(pk=request.POST['cid'])
p.city_id = city
p.save()

c['profile_edit_form'] = profile_edit_form
return render_to_response('profile/edit.html', c,
context_instance=RequestContext(request))

template

in my template {{ profile_edit_form }} #shows the city id not the
actual city name refered to by the id ?

thanks

Re: is my UserProfile ManyToMany wrong?

2012-02-12T12:15:00.000-08:00

Thanks Patrick and Daniel i got it working with adding the unicode
method. much appreciated.

On Feb 12, 3:49 pm, Patrick Wellever <pwelle...@gmail.com> wrote:
> Hi,
>
> Is that code all that's in your model classes, or just an excerpt? If you
> don't already have a __unicode__() method defined on your model, I think
> that would cause the problem you are referring to. That method would be
> called by Django in various places, wherever it needs to represent a model
> object as a string.
>
> Try:
>
> class Interests(models.Model):
> # eg hockey, gaming, etc
> interest = models.CharField(max_length=100)
> class Meta:
> db_table = u'interests'
>
> def __unicode__(self):
> return self.interest
>
> Hope that's helpful.
>
> Best,
> Patrick
>
>
>
>
>
>
>
> On Sun, Feb 12, 2012 at 6:06 AM, richard <pullenjenn...@gmail.com> wrote:
> > Hi im having difficulty looping over my mantomany in my template. A
> > user has a 1to1 with UserProfile and the UserProfile has a manytomany
> > with interests. But displaying the form field without looping over it
> > displays a model multiple select with just a list of object result
> > sets. displaying interests object in the list.
>
> > code
> > models.py
>
> > class Interests(models.Model):
> > # eg hockey, gaming, etc
> > interest = models.CharField(max_length=100)
> > class Meta:
> > db_table = u'interests'
>
> > class UserProfile(models.Model):
> > user = models.OneToOneField(User)
> > interests = models.ManyToManyField(Interests)
>
> > ...

Re: is my UserProfile ManyToMany wrong?

2012-02-12T11:03:00.000-08:00

On Sunday, 12 February 2012 11:06:32 UTC, richard wrote:

Hi im having difficulty looping over my mantomany in my template. A
user has a 1to1 with UserProfile and the UserProfile has a manytomany
with interests. But displaying the form field without looping over it
displays a model multiple select with just a list of object result
sets. displaying interests object in the list.

code
models.py

class Interests(models.Model):
# eg hockey, gaming, etc
interest = models.CharField(max_length=100)
class Meta:
db_table = u'interests'

class UserProfile(models.Model):
user = models.OneToOneField(User)
interests = models.ManyToManyField(Interests)

forms.py
class ProfileEditForm(ModelForm):
class Meta:
model = UserProfile

views.py
def edit(request):
c = {}
c.update(csrf(request))
profile_edit_form =
ProfileEditForm(instance=request.user.get_profile())
if request.method == "POST":
pass

c['profile_edit_form'] = profile_edit_form
return render_to_response('profile.html', c,
context_instance=RequestContext(request))

template
{{ profile_edit_form.interests}} # which displays multipleselect with
values as 'interests object' becuase i cant loop over it to get
interest

heres my attempts to loop over it
attempt 1
{% for interest in profile_edit_form.interests.all %} # seems to be no
results in all
{{ interest.interest }}
{ % endfor %}

attempt2
{% for interest in profile_edit_form.interests_set.all %} # seems to
be no results in all
{{ interest.interest }}
{ % endfor %}

attempt3
{% for interest in profile_edit_form.userprofile_interests.all %} #
seems to be no results in all
{{ interest.interest }}
{ % endfor %}

Am i going wrong somehow.?

thanks.

You're trying to iterate over a form field as if it's a model field or a queryset, which it isn't. `user_profile.interests` has an `.all()` manager, but `profile_form.interests` doesn't.

As pw points out, if you define a `unicode` on the interests class, its value will be used when rendering the field. Otherwise, as the documentation[1] states, you can subclass ModelChoiceField to override `label_from_instance` to return a custom value.

[1]: https://docs.djangoproject.com/en/1.3/ref/forms/fields/#modelchoicefield

DR.

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Re: Where is linebreaksbr function ?

2012-02-12T10:02:00.001-08:00

> What's so difficult about
>
> "<br />".join(data.split("\n"))

Nothing ? But that's not what I wanted.
1) It can't escape.
2) If I would have wanted something like that I would have use
data.replace('\n', '<br />') which is a whole lot faster than your
solution.

Re: pysqlite installation

2012-02-12T10:00:00.001-08:00

Actually, If you're using the the sqlite3 backend for Django, you DO NOT have to use any `pysqlite'. The sqlite3 db-API has been a part of the Python standard library for long, and even if we ignore that, if you stick to Django's wonderful ORM, you shouldn't really have to work directly with pysqlite. I can understand if the DB was something like MongoDB or Redis, but SQLite3 should not bother you much.

On Sun, Feb 12, 2012 at 10:17 PM, Dennis Lee Bieber <wlfraed@ix.netcom.com> wrote:

On Sun, 12 Feb 2012 06:17:23 -0800 (PST), Marcus Maximus
<marcus.presich@gmail.com> wrote:

>My python version:
>ActivePython 2.7.2.5 (ActiveState Software Inc.) based on Python 2.7.2
>(default, Jun 24 2011, 12:21:10) [MSC v.1500 32 bit (Intel)] on win 32

SQLite3, and the Python DB-API for it have been a part of Python's
standard library since, what, Python 2.5?

There is nothing that needs to be installed to use it.

>
>and my db:
>postgresql 1.14.1 also on win 7
>
>can sb help me to install the pysqlite database adapter?
>

I suspect you are confused about what you need to install. Pysqlite
works with SQLite3 database engine.

For use with PostgreSQL you need to install a PostgreSQL adapter:
psycopg2 seems to be the common package, there are others which may or
may not be as complete a match for the DB-API 2 specification.
--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/

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Re: Where is linebreaksbr function ?

2012-02-12T08:47:00.001-08:00

On Sun, 12 Feb 2012 07:53:43 -0800 (PST), Nolhian <Eldurian@hotmail.com>
wrote:

>Hello,
>
>I've found linebreaks, urlize and so on in django.utils.html but
>linebreaksbr is not there. I need it to format my data inside my view
>instead of the template.
>

What's so difficult about

"<br />".join(data.split("\n"))
--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/

Re: pysqlite installation

2012-02-12T08:47:00.000-08:00

On Sun, 12 Feb 2012 06:17:23 -0800 (PST), Marcus Maximus
<marcus.presich@gmail.com> wrote:

>My python version:
>ActivePython 2.7.2.5 (ActiveState Software Inc.) based on Python 2.7.2
>(default, Jun 24 2011, 12:21:10) [MSC v.1500 32 bit (Intel)] on win 32

SQLite3, and the Python DB-API for it have been a part of Python's
standard library since, what, Python 2.5?

There is nothing that needs to be installed to use it.
>
>and my db:
>postgresql 1.14.1 also on win 7
>
>can sb help me to install the pysqlite database adapter?
>

I suspect you are confused about what you need to install. Pysqlite
works with SQLite3 database engine.

For use with PostgreSQL you need to install a PostgreSQL adapter:
psycopg2 seems to be the common package, there are others which may or
may not be as complete a match for the DB-API 2 specification.
--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/

Re: Django Comments Form not Displaying

2012-02-12T08:37:00.000-08:00

Excerpts from Michael P. Soulier's message of 2012-02-12 14:16:26 -0200:
> On 12/02/12 coded kid said:
>
> > Below is the codes in my comments/form.html
> > {% load comments i18n %}
> > <form action="{% comment_form_target %}" method="post">{% csrf_token
> > %}
> > {% if next %}<div><input type="hidden" name="next"
> > value="{{ next }}" /></div>{% endif %}
> > {% for field in form %}
> > {% if field.is_hidden %}
> > <div>{{ field }}</div>
> > {% else %}
> > {% if field.errors %}{{ field.errors }}{% endif %}
> > <p
> > {% if field.errors %} class="error"{% endif %}
> > {% ifequal field.name "honeypot" %} style="display:none;"{%
> > endifequal %}>
> > {{ field.label_tag }} {{ field }}
> > </p>
> > {% endif %}
> > {% endfor %}
> > <p class="submit">
> > <input type="submit" name="post" class="submit-post" value="{%
> > trans "Post" %}" />
> > <input type="submit" name="preview" class="submit-preview"
> > value="{% trans "Preview" %}" />
> > </p>
> > </form>
>
> You have conditionals on all output. If you're seeing a blank page, perhaps
> those conditionals are all false. Put in some unconditional content and see if
> it renders, and then start testing your conditionals.

"/comments/post" is decorated by require_POST, that means that POST is the only
method allowed to access that view, check your response, you should be getting
a 405 response.

You should include the form in the page you want it to display, let's say
a blog post page, but if you want the form on a single page, then you need to
define a different URL and view to render the template.

Regards,
Matías
--
Matías Aguirre (matiasaguirre@gmail.com)

Re: Django Comments Form not Displaying

2012-02-12T08:16:00.000-08:00

On 12/02/12 coded kid said:

> Below is the codes in my comments/form.html
> {% load comments i18n %}
> <form action="{% comment_form_target %}" method="post">{% csrf_token
> %}
> {% if next %}<div><input type="hidden" name="next"
> value="{{ next }}" /></div>{% endif %}
> {% for field in form %}
> {% if field.is_hidden %}
> <div>{{ field }}</div>
> {% else %}
> {% if field.errors %}{{ field.errors }}{% endif %}
> <p
> {% if field.errors %} class="error"{% endif %}
> {% ifequal field.name "honeypot" %} style="display:none;"{%
> endifequal %}>
> {{ field.label_tag }} {{ field }}
> </p>
> {% endif %}
> {% endfor %}
> <p class="submit">
> <input type="submit" name="post" class="submit-post" value="{%
> trans "Post" %}" />
> <input type="submit" name="preview" class="submit-preview"
> value="{% trans "Preview" %}" />
> </p>
> </form>

You have conditionals on all output. If you're seeing a blank page, perhaps
those conditionals are all false. Put in some unconditional content and see if
it renders, and then start testing your conditionals.

Mike

Django Comments Form not Displaying

2012-02-12T08:09:00.001-08:00

Hi guys, please help me out with django-comments form. I added :
'django.contrib.comments', to INSTALLED APPS

(r'^comments/', include('django.contrib.comments.urls')), to urls.py
and I copied the default templates from
django.contrib.comments.templates.comments to my app templates
directory.

After doing that, I visit localhost:8000/comments/posts and the page
is not showing me any comments form, it just showing me a white blank
page. What I'm I doing wrong?

Below is the codes in my comments/form.html
{% load comments i18n %}
<form action="{% comment_form_target %}" method="post">{% csrf_token
%}
{% if next %}<div><input type="hidden" name="next"
value="{{ next }}" /></div>{% endif %}
{% for field in form %}
{% if field.is_hidden %}
<div>{{ field }}</div>
{% else %}
{% if field.errors %}{{ field.errors }}{% endif %}
<p
{% if field.errors %} class="error"{% endif %}
{% ifequal field.name "honeypot" %} style="display:none;"{%
endifequal %}>
{{ field.label_tag }} {{ field }}
</p>
{% endif %}
{% endfor %}
<p class="submit">
<input type="submit" name="post" class="submit-post" value="{%
trans "Post" %}" />
<input type="submit" name="preview" class="submit-preview"
value="{% trans "Preview" %}" />
</p>
</form>
Hope to hear from you soon.

Re: Where is linebreaksbr function ?

2012-02-12T08:08:00.001-08:00

autoreponsse : Found it ! It's in django.template.defaultfilters,
linebreaks is there too !

On Feb 12, 4:53 pm, Nolhian <Eldur...@hotmail.com> wrote:
> Hello,
>
> I've found linebreaks, urlize and so on in django.utils.html but
> linebreaksbr is not there. I need it to format my data inside my view
> instead of the template.
>
> Any idea of its location ?
>
> Thanks in advance,
> Nolhian

Where is linebreaksbr function ?

2012-02-12T07:53:00.000-08:00

Hello,

I've found linebreaks, urlize and so on in django.utils.html but
linebreaksbr is not there. I need it to format my data inside my view
instead of the template.

Any idea of its location ?

Thanks in advance,
Nolhian

Re: is my UserProfile ManyToMany wrong?

2012-02-12T07:49:00.000-08:00

Hi,

Is that code all that's in your model classes, or just an excerpt? If you don't already have a __unicode__() method defined on your model, I think that would cause the problem you are referring to. That method would be called by Django in various places, wherever it needs to represent a model object as a string.

Try:

class Interests(models.Model):

# eg hockey, gaming, etc

interest = models.CharField(max_length=100)

class Meta:

db_table = u'interests'

def __unicode__(self):

return self.interest

Hope that's helpful.

Best,

Patrick

On Sun, Feb 12, 2012 at 6:06 AM, richard <pullenjenna10@gmail.com> wrote:

Hi im having difficulty looping over my mantomany in my template. A
user has a 1to1 with UserProfile and the UserProfile has a manytomany
with interests. But displaying the form field without looping over it
displays a model multiple select with just a list of object result
sets. displaying interests object in the list.

code
models.py

class Interests(models.Model):
# eg hockey, gaming, etc
interest = models.CharField(max_length=100)
class Meta:
db_table = u'interests'

class UserProfile(models.Model):
user = models.OneToOneField(User)
interests = models.ManyToManyField(Interests)

...

Is django-syncr dead?

2012-02-12T07:45:00.000-08:00

Good day Djangonauts!

I'm wondering if anyone knows anything about django-syncr (http://code.google.com/p/django-syncr/). The PyPI page hasn't been updated for a year, and I think some of the YouTube API has changed. I'm bringing an old project that relied pretty heavily on django-sycr up to Django 1.3.1, and it's not playing very nicely. I'm able to hack my way through the code to get it to work, but there's always a better way than that, right? Questions:

Is there something out there that I should be using besides django-syncr? Always interested in best practices.
If not, is there any interest in reviving this project? I'd be happy to contribute.
Any code out there that hasn't been committed that could be?
Anyone using django-syncr (particularly the YouTube parts) and new syncs are working properly? It seems to be trying non-exisitent URLs.

--
Kevin Harvey
Web Developer
kcharvey@gmail.com
@kevinharvey

Re: sqlite3 error

2012-02-12T06:42:00.000-08:00

On 12-02-12 15:31, Marcus Maximus wrote:
> I tried to change the setting.py on line 'ENGINE': 'sqlite3', but
> this seems ok in my eyes...
>
> so whats wrong?

Try the full dotted path, so including django.db.backends:

'ENGINE': 'django.db.backends.sqlite3',

Just "sqlite3" by itself was fine in older django versions, so you might
have picked up an example from there.

Reinout

--
Reinout van Rees http://reinout.vanrees.org/
reinout@vanrees.org http://www.nelen-schuurmans.nl/
"If you're not sure what to do, make something. -- Paul Graham"

Re: sqlite3 error

2012-02-12T06:36:00.000-08:00

Try:

django.db.backends.sqlite3

instead of just

sqlite3

On Sun, Feb 12, 2012 at 3:31 PM, Marcus Maximus <marcus.presich@gmail.com> wrote:

Hey guys,

i am trying to configure sqlite3(cause it seems to be easier than
postgresql) for django:

my setting.py file is:

DATABASES = {
'default': {
'ENGINE': 'sqlite3', #'django.db.backends.', # Add
'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
'NAME': 'C:\Users\PythonUser\Desktop\Webseite\Django\sqlite-
shell-win32-x86-3071000\test.db', # Or path to
database file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for
default. Not used with sqlite3.
}
}

I am getting this error:
[quote]

>>> from django.db import connection
>>> cursor = connection.cursor()
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "C:\Python27\lib\site-packages\django\db\backends\dummy
\base.py", line 15
, in complain
raise ImproperlyConfigured("You haven't set the database ENGINE
setting yet.
")
ImproperlyConfigured: You haven't set the database ENGINE setting yet.

[/quote]

I tried to change the setting.py on line 'ENGINE': 'sqlite3', but
this seems ok in my eyes...

so whats wrong?

grettings and a BIG THX in advance

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sqlite3 error

2012-02-12T06:31:00.000-08:00

Hey guys,

i am trying to configure sqlite3(cause it seems to be easier than
postgresql) for django:

my setting.py file is:

DATABASES = {
'default': {
'ENGINE': 'sqlite3', #'django.db.backends.', # Add
'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
'NAME': 'C:\Users\PythonUser\Desktop\Webseite\Django\sqlite-
shell-win32-x86-3071000\test.db', # Or path to
database file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for
default. Not used with sqlite3.
}
}

I am getting this error:
[quote]

>>> from django.db import connection
>>> cursor = connection.cursor()
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "C:\Python27\lib\site-packages\django\db\backends\dummy
\base.py", line 15
, in complain
raise ImproperlyConfigured("You haven't set the database ENGINE
setting yet.
")
ImproperlyConfigured: You haven't set the database ENGINE setting yet.

[/quote]

I tried to change the setting.py on line 'ENGINE': 'sqlite3', but
this seems ok in my eyes...

so whats wrong?

grettings and a BIG THX in advance

pysqlite installation

2012-02-12T06:17:00.000-08:00

Hey guys,

i am trying to install pysqlite under win 7, but the installation
routine always terminates...(I always have to kill the process ,cause
the installation routine always hangs on)

My python version:
ActivePython 2.7.2.5 (ActiveState Software Inc.) based on Python 2.7.2
(default, Jun 24 2011, 12:21:10) [MSC v.1500 32 bit (Intel)] on win 32

and my db:
postgresql 1.14.1 also on win 7

can sb help me to install the pysqlite database adapter?

I thank you in advance for your time and attention and look forward to
your reply;D

greetings

is my UserProfile ManyToMany wrong?

2012-02-12T03:06:00.001-08:00

Hi im having difficulty looping over my mantomany in my template. A
user has a 1to1 with UserProfile and the UserProfile has a manytomany
with interests. But displaying the form field without looping over it
displays a model multiple select with just a list of object result
sets. displaying interests object in the list.

code
models.py

class Interests(models.Model):
# eg hockey, gaming, etc
interest = models.CharField(max_length=100)
class Meta:
db_table = u'interests'

class UserProfile(models.Model):
user = models.OneToOneField(User)
interests = models.ManyToManyField(Interests)

forms.py
class ProfileEditForm(ModelForm):
class Meta:
model = UserProfile

views.py
def edit(request):
c = {}
c.update(csrf(request))
profile_edit_form =
ProfileEditForm(instance=request.user.get_profile())
if request.method == "POST":
pass

c['profile_edit_form'] = profile_edit_form
return render_to_response('profile.html', c,
context_instance=RequestContext(request))

template
{{ profile_edit_form.interests}} # which displays multipleselect with
values as 'interests object' becuase i cant loop over it to get
interest

heres my attempts to loop over it
attempt 1
{% for interest in profile_edit_form.interests.all %} # seems to be no
results in all
{{ interest.interest }}
{ % endfor %}

attempt2
{% for interest in profile_edit_form.interests_set.all %} # seems to
be no results in all
{{ interest.interest }}
{ % endfor %}

attempt3
{% for interest in profile_edit_form.userprofile_interests.all %} #
seems to be no results in all
{{ interest.interest }}
{ % endfor %}

Am i going wrong somehow.?

thanks.

Re: Automatically block requests from bad IP addresses

2012-02-12T02:27:00.001-08:00

That's pretty cute, we use a similar type of DDoS protection method in our webapps too, along with an abusive IP register (albeit ours isn't based on RPM - requests per minute).

You might also want to consider looking at CloudFlare (free for even huge amounts of traffic), as they maintain a *huge* list like this as well.

If you wanted to extend on this even further, you could look at potentially offering a free/public abusive IP register... (we actually maintain several private abusive IP registers for our clients, they are invaluable!) - you just need to make sure every restriction is categorized. I might even consider donating to the cause by giving out some of our registers in the future - as a project like that would depend solely on user contributions from high traffic/attention sites.

Either way, cool work, thanks for sharing!

Cal

On Sat, Feb 11, 2012 at 8:26 AM, Addy Yeow <ayeowch@gmail.com> wrote:

I was looking for a Django solution to automatically block requests from bad IP addresses to some of my apps.

After searching for a while without much luck, I attempted to write a simple Python script that:

- parses my Apache access log
- block IP that made too many requests within a set interval

I have made the script with the associated Django app available on Github for those who may find it useful:

https://github.com/ayeowch/banshee

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Re: Unit test example for web froms

2012-02-12T01:31:00.000-08:00

Coming from a non python/django background (my experience is groovy/
grails), but when we test our controllers (I think this is equivalent
to django views). We simply set up mock params on the request and set
expectations on the controller properties.

Simple example:

given:
request.params = [ param1: 'valid', param2: 'invalid' ]

when:
controller.submit() // the method called when the webform is
posted

then:
controller.hasErrors == true

and:
controller.param2.error == 'this is invalid'

The above example is obviously simplified, but hopefully it shows the
general idea.

On Feb 12, 2:41 am, Mario Gudelj <mario.gud...@gmail.com> wrote:
> Hi guys,
>
> I was wandering if anyone has a good example of a unit test where they have
> a view which processes a web form. I'm not sure how you'd test something
> like that.
>
> Thanks,
>
> mario

Unit test example for web froms

2012-02-11T23:41:00.001-08:00

Hi guys,

I was wandering if anyone has a good example of a unit test where they have a view which processes a web form. I'm not sure how you'd test something like that.

Thanks,

mario

Re: What Can I use?

2012-02-11T23:32:00.000-08:00

On 11/02/2012 9:38pm, coded kid wrote:
> Hey guys, anyone know about a django package I can use for comment in
> django site? The one I see is Django-comment but it's not maintained
> anymore. What other one do you know about? Thanks.

Is there something wrong with django.contrib.comments ???

It is built into the Django distribution. Sort of "batteries included".

https://docs.djangoproject.com/en/1.3/ref/contrib/comments/example/

Mike

Re: What Can I use?

2012-02-11T21:44:00.000-08:00

For those packages, I wonder where I can find a demo about how they look ?

Thanks very much

Best regards

On Sat, Feb 11, 2012 at 8:24 AM, Kevin Harvey <kcharvey@gmail.com> wrote:

I always look at djangopackages.com for questions like this: http://djangopackages.com/grids/g/commenting/

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Re: How do I sort choices by their localized label?

2012-02-11T12:52:00.000-08:00

> class CountryField(models.CharField):
> def __init__(self, *args, **kwargs):
> kwargs.setdefault('max_length', 2)
> kwargs.setdefault('choices', COUNTRIES)
> super(CountryField, self).__init__(*args, **kwargs)

Btw, the reason this doesn't work is because setdefault doesn't work
as you think it does. See [1] for an example.

For the 'layer violation', you might try:

class CountryField(models.CharField):
def __init__(self, *args, **kwargs):
super(CountryField, self).__init__(*args, **kwargs)
self.choices = sorted(COUNTRIES, key=lambda c: c[1])
...

I haven't tried this but it might work.
Cheers

[1]http://www.saltycrane.com/blog/2010/02/python-setdefault-example/

Re: Digest for django-users@googlegroups.com - 18 Messages in 8 Topics

2012-02-11T11:39:00.000-08:00

I have configured the tinymce, but I can't get the local file browsing... and leads...?

thanx...

Re: How do I sort choices by their localized label?

2012-02-11T11:20:00.000-08:00

On Saturday, February 11, 2012 7:32:09 PM UTC+2, ajohnston wrote:

Have you tried setting the choices in your form, like:

class SomeFormUsingCountryField(forms.Form):
def __init__(self, *args, **kwargs):
super(SomeFormUsingCountryField, self).__init__(*args,
**kwargs)
self.fields['country_field'].choices = sorted(COUNTRIES,
key=lambda c: c[1])

Funny, that fixes it. Thanks!

It's a layer violation, so I have to do it for each form that uses my field, but it works.

Salvatore.

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Re: Mod_Wsgi + Apache 2.2 + Threads + httplib2

2012-02-11T11:08:00.001-08:00

Just to give more details that I think can be relevant:
"Hi everyone,
I have a django application that works pretty fine with django web-
server.
I have a python file that uses Http() from httplib2, it works very
well! But when I create a thread and in this thread use this python
file(more precisely a class) that uses Http() it seems that I got in a
infinite loop.
I am very noob in this kind of problems, but I think the problem is in
Apache or mod_wsgi because if I use django webserver it works as well!
But if I use Apache2 + mod_wsgi it doesn't work! Other strange thing
is that in my house it works ;/, it doesn't work at my server ;(.
If I use this class(that calls Http() ) without a thread involving it,
it works fine too ;/.
This my configuration Apache/2.2.14 (Ubuntu) DAV/2 SVN/1.6.6 PHP/
5.3.2-1ubuntu4.10 with Suhosin-Patch mod_wsgi/3.3 Python/2.7
configured -- resuming normal operations
I have tested with other python version too.
My httpd.conf:
###
LoadModule wsgi_module /usr/lib/apache2/modules/mod_wsgi.so
WSGIScriptAlias / /srv/www/ufcgjudge/apache/django.wsgi
########
At sites-available/ufcgjudge:
"""
WSGIDaemonProcess ufcgjudge processes=2 threads=15 display-name=%
{GROUP}
WSGIProcessGroup ufcgjudge

WSGIScriptAlias / /srv/www/ufcgjudge/apache/django.wsgi
"""
Exactly the same way that is in my house.(And works here!)

On Feb 11, 3:02 pm, Phyllipe <phyllipece...@gmail.com> wrote:
> My server config: Apache/2.2.14 (Ubuntu) DAV/2 SVN/1.6.6 PHP/
> 5.3.2-1ubuntu4.10 with Suhosin-Patch mod_wsgi/3.3 Python/2.6.5
> configured -- resuming normal operations
> There is no error at apache log.
> I've tried to put:
> try:
> ...response, content...
> ...print "NEXT"
> except Exception as detail:
> ..print detail
> None of those prints were used ;/ Seems that I get an infinite loop at
> response, content...
> But just saying again, if I try "response, content" without using a
> thread, it works very nice!
> And if I try response, content with django webserver it works nice
> too!
>
> On Feb 11, 11:37 am, Phyllipe <phyllipece...@gmail.com> wrote:
>
>
>
>
>
>
>
> > I have a python file that works as well, it connects in another
> > website, doing something like that:
> > 'response, content = self.http.request('http://www.spoj.pl/', 'POST',
> > headers=self.headers, body=urlencode(self.bodyLogin))'
> > It goes inside a class, when I run it in a thread it does not works.
> > If I try with runserver it works as well! But with Apache2 and
> > MOD_WSGI doesnt work!
> > I debugged somethings, I've tried to connect without using the
> > thread(calling the method in some view) and it worked.
> > But when I use my SingleTon class that has a bounded semaphores that
> > creates a thread and in that thread class this method that was talking
> > before, it stops in the response, content part.
> > So I did a little more tests, I've created a thread in my views and in
> > that thread called this method exactly the same way that I called
> > without threads and that worked, but it has not worked ;/
> > I've putted some prints in my code that is how I discovered the line
> > that has the bug, I've putted a print before call 'response, content'
> > and a print after, the before print appears but not the last, the
> > strange thing its that does not raise any kind of exception, cause I
> > have a try:, except Exception in a while True and it does not executes
> > the before print again...
> > some thing like
> > while True:
> > ....try:
> > ........print
> > ........response....
> > ....except Exception as detail:
> > .......pass
> > So I'm pretty sure that my bug is something related to Threads +
> > httplib2, if I use only httplib2 works as well!
> > If I use only django server works as well if threads and httplib2.
> > But when I try to deploy in my university server with apache2 and
> > mod_wsgi it bugs ;/
> > At my house with apache2 and mod_wsgi works as well
> > I have already installed apache2-threaded-dev...

Re: Mod_Wsgi + Apache 2.2 + Threads + httplib2

2012-02-11T10:02:00.000-08:00

My server config: Apache/2.2.14 (Ubuntu) DAV/2 SVN/1.6.6 PHP/
5.3.2-1ubuntu4.10 with Suhosin-Patch mod_wsgi/3.3 Python/2.6.5
configured -- resuming normal operations
There is no error at apache log.
I've tried to put:
try:
...response, content...
...print "NEXT"
except Exception as detail:
..print detail
None of those prints were used ;/ Seems that I get an infinite loop at
response, content...
But just saying again, if I try "response, content" without using a
thread, it works very nice!
And if I try response, content with django webserver it works nice
too!

On Feb 11, 11:37 am, Phyllipe <phyllipece...@gmail.com> wrote:
> I have a python file that works as well, it connects in another
> website, doing something like that:
> 'response, content = self.http.request('http://www.spoj.pl/', 'POST',
> headers=self.headers, body=urlencode(self.bodyLogin))'
> It goes inside a class, when I run it in a thread it does not works.
> If I try with runserver it works as well! But with Apache2 and
> MOD_WSGI doesnt work!
> I debugged somethings, I've tried to connect without using the
> thread(calling the method in some view) and it worked.
> But when I use my SingleTon class that has a bounded semaphores that
> creates a thread and in that thread class this method that was talking
> before, it stops in the response, content part.
> So I did a little more tests, I've created a thread in my views and in
> that thread called this method exactly the same way that I called
> without threads and that worked, but it has not worked ;/
> I've putted some prints in my code that is how I discovered the line
> that has the bug, I've putted a print before call 'response, content'
> and a print after, the before print appears but not the last, the
> strange thing its that does not raise any kind of exception, cause I
> have a try:, except Exception in a while True and it does not executes
> the before print again...
> some thing like
> while True:
> ....try:
> ........print
> ........response....
> ....except Exception as detail:
> .......pass
> So I'm pretty sure that my bug is something related to Threads +
> httplib2, if I use only httplib2 works as well!
> If I use only django server works as well if threads and httplib2.
> But when I try to deploy in my university server with apache2 and
> mod_wsgi it bugs ;/
> At my house with apache2 and mod_wsgi works as well
> I have already installed apache2-threaded-dev...

Re: How do I sort choices by their localized label?

2012-02-11T09:32:00.001-08:00

Sorry I just realized that even though that sorts them correctly, it
doesn't solve your problem.

Have you tried setting the choices in your form, like:

class SomeFormUsingCountryField(forms.Form):
def __init__(self, *args, **kwargs):
super(SomeFormUsingCountryField, self).__init__(*args,
**kwargs)
self.fields['country_field'].choices = sorted(COUNTRIES,
key=lambda c: c[1])

Re: How do I sort choices by their localized label?

2012-02-11T08:59:00.000-08:00

I think this should work:

>>> COUNTRIES = (
... ('GB', _('United Kingdom')),
... ('AF', _('Afghanistan')),
... ('AX', _('Aland Islands')),
... ('AL', _('Albania')),
... ('DZ', _('Algeria')),)

>>> sorted(COUNTRIES, key=lambda COUNTRIES: COUNTRIES[1])
[('AF', 'Afghanistan'), ('AX', 'Aland Islands'), ('AL', 'Albania'),
('DZ', 'Algeria'), ('GB', 'United Kingdom')]

Re: list_editable raising a MultiValueDictKeyError

2012-02-11T07:49:00.000-08:00

I added the missing form inputs as follows:

if ($('.editable').length > 0) {
$('.action-select').each(function(i, el) {
var item_id = $(el).val();
$('form').append("<input type='hidden' name='form-" + i + "-id'
value='" + item_id + "'/>");
});
}

It seems a bug

On Feb 7, 9:10 pm, Nick <nickt...@gmail.com> wrote:
> Whenever I use list_editable inside of the django admin attempting to
> save the data results in
>
> Exception Type: MultiValueDictKeyError
> Exception Value: "Key 'form-0-id' not found in <QueryDict: {u'form-66-
> newID': [u''], etc. etc. >
>
> Whenever I create custom forms I simply add in the form-0 inputs as a
> hidden field. How do I work around this in the admin?

Re: User .get_all_permissions() vs. .has_perm() inconsistency

2012-02-11T07:38:00.001-08:00

Yes, I have to agree entirely..
I bungled the OP. Here is what the code snippet should have been:
>>> from django.contrib.auth.models import User
>>> u = User.objects.get(username='clint')
>>> u.get_all_permissions()
set([u'wb.delete_libraryitem', u'wb.change_libraryitem'])
>>> u.has_perm("wb.add_libraryitem")
True

How can that be?

Your reply did prod me into realizing that I had made a similar typo
while trying to resolve this question last night. Anyway, here is the
answer:
>>> u.is_superuser
True

If the user is not superuser, it returns False. u.has_perm() returns
true for ANY permission if u is superuser.
>>> u.has_perm("wb.anything")
True

This solves the problem. Thanks for the help Andy. :)

Don Slowik

On Feb 10, 10:49 pm, Andy McKay <a...@clearwind.ca> wrote:
> On Fri, Feb 10, 2012 at 4:01 PM, dslowik <dslo...@tellink.net> wrote:
> >>>> u.get_all_permissions()
> > set([u'wb.delete_libraryitem', u'wb.change_libraryitem'])
> >>>> u.has_perm("wb.change_libraryitem")
> > True
>
> > ...Shouldn't that be False?
>
> Why would it be False? get_all_permissions: Returns a set of
> permission strings that the user has.... has_perm: Returns True if the
> user has the specified permission.
>
> https://docs.djangoproject.com/en/1.2/topics/auth/#django.contrib.aut...

Re: Generating a list of available templates

2012-02-11T07:30:00.000-08:00

Thanks for weighing in, that is helpful, and last night I was playing around with a somewhat similar approach. It's not exactly what I was hoping for, because it still isn't really integrated with the way Django uses template loaders.

This solution works for TEMPLATE_DIRS and INSTALLED_APPS, but there are other possible template loaders, or a user might have written a custom template loader. Or they may have disabled the app directories loader… Anyway, you get the idea.

If the built-in loader classes had some method that would just return the paths to the template directories that were loaded, this could work perfectly, but I think the loaders can only check to see if a supplied template name exists on one of the paths they serve. So it seems like my idea is not really feasible in a way that integrates cleanly with Django and results in a portable application. Thanks to everyone who replied with assistance.

- Patrick

On Saturday, February 11, 2012 at 5:39 AM, bb6xt wrote:

Here's my two cents. Hope it helps some.

from proj.settings import TEMPLATE_DIRS, INSTALLED_APPS
import os

def recursive_search(path):
result = []
for i in os.listdir(path):
if not os.path.isdir(os.path.join(path, i)):
result.append(i)
else:
result.extend(recursive_search(os.path.join(path, i)))
return result

def myview(request):
templates = []
# the next 2 lines handles templates in explicit template
directories
for path in TEMPLATE_DIRS:
templates.extend(recursive_search(path))
# the next 2 will handle template dir generated py the
appdirectories loader excluding contrib apps
for app in INSTALLED_APPS:
if app.startswith('proj'):
if os.path.exists(os.path.join(ABSPATH_TO_PROJ,
app.split('.')[-1], 'templates')):

templates.extend(recursive_search(os.path.join(ABSPATH_TO_PROJ,
app.split('.')[-1], 'templates')))

well, you have a list of templates with which you can do as you
please. surely you'll want to keep track of the actual path django
uses to locate these templates, you can do so by tweaking the
recursive_search funct a little

Re: django discarding MySQL results for "in" operator

2012-02-11T06:54:00.000-08:00

Karen Tracey <kmtracey <at> gmail.com> writes:

>
>
> On Mon, Jan 5, 2009 at 3:37 PM, JonUK <jdoull <at> flinttechnology.co.uk>
wrote:
>
>
>
> Apologies as this is a repost, but I'm completely stuck!
> I'm using django 1.0.2 and the tagging app to retrieve a tag via a
> database "in" query, and something is causing the query results to be
> discarded.
> In particular, this line of code from tagging.utils.get_tag_list()
> executes:
> return Tag.objects.filter(name__in=[force_unicode(tag)
> for tag in tags])
> and at this point:
> (Pdb) p tags
> [u'sea']
> The thread of execution can be traced into the method
> django.db.models.sql.query.execute_sql(self, result_type=MULTI), and
> to this line of code:
> cursor.execute(sql, params)
> and over here:
> >
> c:\python26\lib\site-packages\django\db\models\sql\query.py(1735)
> execute_sql()
> -> cursor.execute(sql, params)
> (Pdb) p sql
> 'SELECT "tagging_tag"."id", "tagging_tag"."name" FROM "tagging_tag"
> WHERE "tagging_tag"."name" IN (%s) ORDER BY "tagging_tag"."name" ASC'
> (Pdb) p params
> (u'sea',)
> (Pdb)
> If I audit what's submitted to MySQL via MySQL logging, it reports:
> SELECT `tagging_tag`.`id`, `tagging_tag`.`name` FROM `tagging_tag`
> WHERE `tagging_tag`.`name` IN ('sea') ORDER BY `tagging_tag`.`name`
> ASC
> which looks correct - however django returns an empty list.
> If I execute the query interactively in MySQL, I get the expected
> (correct) result:
> +----+------+
> | id | name |
> +----+------+
> | 28 | Sea |
> +----+------+
> 1 row in set (0.00 sec)
> I suspect this is a configuration problem but have no idea where to
> look - can anyone help?
>
>
> I can't recreate with a similar (though without tagging, just doing a similar
in query for one of my models) query on my MySQL DB/django app. The
.filter(xxxx__in=[...]) returns case-insensitive results as expected. As you've
traced it down to where the SQL executes, have you gone farther to determine if
somehow that SQL query when issued by Django isn't returning any results while
the one you issue in the mysql command does? It'd be pretty bizarre, but maybe
the SQL is returning the same result but somehow it's getting lost before the
.filter() is returning? The alternative seems to be that the same SQL query is
returning different results, which seems equally bizarre. (There is no
configuration option to change what collation is used for the query, which is
all I could think would change the result as you have described -- Django always
uses the default collation.)Karen
>
>
> --~--~---------~--~----~------------~-------~--~----~
> You received this message because you are subscribed to the Google Groups
"Django users" group. To post to this group, send email to django-users <at>
googlegroups.com To unsubscribe from this group, send email to django-
users+unsubscribe <at> googlegroups.com For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
> -~----------~----~----~----~------~----~------~--~---
>

Apologies for the long silence before responding. Although I do not recall if
this was the precisely the issue (it was a long time ago), I did eventually hunt
down an accepted bug in Mysql that makes the "in" clause unreliable,
particularly when used in subqueries. The recommended workaround was to replace
with joins, however my preferred solution was to use Postgres, which solved this
problem and worked a treat. I appreciated your responses - so thank you.

Mod_Wsgi + Apache 2.2 + Threads + httplib2

2012-02-11T06:37:00.000-08:00

I have a python file that works as well, it connects in another
website, doing something like that:
'response, content = self.http.request('http://www.spoj.pl/', 'POST',
headers=self.headers, body=urlencode(self.bodyLogin))'
It goes inside a class, when I run it in a thread it does not works.
If I try with runserver it works as well! But with Apache2 and
MOD_WSGI doesnt work!
I debugged somethings, I've tried to connect without using the
thread(calling the method in some view) and it worked.
But when I use my SingleTon class that has a bounded semaphores that
creates a thread and in that thread class this method that was talking
before, it stops in the response, content part.
So I did a little more tests, I've created a thread in my views and in
that thread called this method exactly the same way that I called
without threads and that worked, but it has not worked ;/
I've putted some prints in my code that is how I discovered the line
that has the bug, I've putted a print before call 'response, content'
and a print after, the before print appears but not the last, the
strange thing its that does not raise any kind of exception, cause I
have a try:, except Exception in a while True and it does not executes
the before print again...
some thing like
while True:
....try:
........print
........response....
....except Exception as detail:
.......pass
So I'm pretty sure that my bug is something related to Threads +
httplib2, if I use only httplib2 works as well!
If I use only django server works as well if threads and httplib2.
But when I try to deploy in my university server with apache2 and
mod_wsgi it bugs ;/
At my house with apache2 and mod_wsgi works as well
I have already installed apache2-threaded-dev...

Re: What Can I use?

2012-02-11T05:24:00.000-08:00

I always look at djangopackages.com for questions like this: http://djangopackages.com/grids/g/commenting/

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Re: How do I sort choices by their localized label?

2012-02-11T05:23:00.001-08:00

Have you tried sorting them at the template level? A filter like dictsort might do the trick https://docs.djangoproject.com/en/dev/ref/templates/builtins/?from=olddocs#dictsort

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compare two querysets

2012-02-11T05:14:00.000-08:00

I’ve got a use case where I need to find the fields that are different between two querysets in the same model and then use those fields to modify another queryset in that model. The first two represent “masks” of allowed fields for a specific version while the third is the actual data. Assessment_id’s below 1000 are templates while >1000 are data.

Based on a date entered in one field (not shown) the version of the form could change and thus the applicable sections could change. This will not happen often and therefore does not need to be efficient. There will be cases where the all the fields in the templates are identical, but it may not be practical to merge those templates due to the need to find/fix design bugs and requirements changes in template definitions.

The best idea I can come up with is to:

Get a queryset for each template based on it’s pk (derived elsewhere)

Convert the __dict__ from each queryset to a set of (name,value) pairs.

Find the differences between the two sets

Convert the remaining set back to a dict() called “changes”

Data = get the queryset for the actual data using it’s pk

Use Data.__dict__( changes)

And of course save

Snippets of models module below:

class MDSSection(models.Model):

assessment = models.OneToOneField(Assessment, primary_key=True)

. . .

class A(MDSSections):

A0100A = models.CharField(max_length=10, help_text='''Text : Facility National Provider Identifier (NPI)''')

A0100B = models.CharField(max_length=12, help_text='''Text : Facility CMS Certification Number (CCN)''')

A0100C = models.CharField(max_length=15, help_text='''Text : State provider number''')

A0200 = models.CharField(max_length= 1, default='1', help_text='''Code : Type of provider''')

A0310A = models.CharField(max_length= 2, help_text='''Code : Type of assessment: OBRA''')

. . .

How do I sort choices by their localized label?

2012-02-11T05:12:00.001-08:00

Hi,

I have the following custom field:

from django.utils.translation import ugettext_lazy as _

COUNTRIES = (

('GB', _('United Kingdom')),

('AF', _('Afghanistan')),

('AX', _('Aland Islands')),

('AL', _('Albania')),

('DZ', _('Algeria')),

)

class CountryField(models.CharField):

def __init__(self, *args, **kwargs):

kwargs.setdefault('max_length', 2)

kwargs.setdefault('choices', COUNTRIES)

super(CountryField, self).__init__(*args, **kwargs)

def get_internal_type(self):

return "CharField"

That field ends up in an HTML <select>, and I'd like the countries to be sorted by their label in all locales. I have tried to replace this code:

kwargs.setdefault('choices', COUNTRIES)

with this:

kwargs.setdefault('choices', sorted(COUNTRIES, key=lambda x: x[1]))

but that's sorting the list only by the original English names, whatever the locale.

I can't switch to ugettext instead of the _lazy version, because this is a Field so it won't work at all.

Do you have any suggestion on how to get my list of countries properly sorted in all locales?

Thank you!

Salvatore Iovene.

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Re: Generating a list of available templates

2012-02-11T02:39:00.000-08:00

Here's my two cents. Hope it helps some.

from proj.settings import TEMPLATE_DIRS, INSTALLED_APPS
import os

def recursive_search(path):
result = []
for i in os.listdir(path):
if not os.path.isdir(os.path.join(path, i)):
result.append(i)
else:
result.extend(recursive_search(os.path.join(path, i)))
return result

def myview(request):
templates = []
# the next 2 lines handles templates in explicit template
directories
for path in TEMPLATE_DIRS:
templates.extend(recursive_search(path))
# the next 2 will handle template dir generated py the
appdirectories loader excluding contrib apps
for app in INSTALLED_APPS:
if app.startswith('proj'):
if os.path.exists(os.path.join(ABSPATH_TO_PROJ,
app.split('.')[-1], 'templates')):

templates.extend(recursive_search(os.path.join(ABSPATH_TO_PROJ,
app.split('.')[-1], 'templates')))

well, you have a list of templates with which you can do as you
please. surely you'll want to keep track of the actual path django
uses to locate these templates, you can do so by tweaking the
recursive_search funct a little

On Feb 11, 2:34 am, Patrick Wellever <pwelle...@gmail.com> wrote:
> Thanks for the reply. Yes, this wouldn't be too tough if the directories in TEMPLATE_DIRS were all I had to worry about, but the glitch I mentioned earlier is that Django can also look for templates in places other than those listed explicitly in that setting.
>
> For example, the template loader 'django.template.loaders.app_directories.Loader', which is enabled by default, looks for a "templates" directory within each one of your "installed apps." So a solution that only considers paths in TEMPLATE_DIRS would not work in that situation.
>
> - Patrick
>
>
>
>
>
>
>
> On Friday, February 10, 2012 at 5:05 PM, Bill Beal wrote:
> > I know nothing, but here's what I did:
>
> > python manage.py shell
> > import os
> > from settings import TEMPLATE_DIRS
> > for x in TEMPLATE_DIRS:
> > print x
> > os.listdir(x)
>
> > It gave me a list of the files in the (each) template directory.
>
> > It looks like you already have a list of template directories in settings.py.

What Can I use?

2012-02-11T02:38:00.001-08:00

Hey guys, anyone know about a django package I can use for comment in
django site? The one I see is Django-comment but it's not maintained
anymore. What other one do you know about? Thanks.

Automatically block requests from bad IP addresses

2012-02-11T00:26:00.000-08:00

I was looking for a Django solution to automatically block requests from bad IP addresses to some of my apps.

After searching for a while without much luck, I attempted to write a simple Python script that:

- parses my Apache access log

- block IP that made too many requests within a set interval

I have made the script with the associated Django app available on Github for those who may find it useful:

https://github.com/ayeowch/banshee

Re: User .get_all_permissions() vs. .has_perm() inconsistency

2012-02-10T19:49:00.001-08:00

On Fri, Feb 10, 2012 at 4:01 PM, dslowik <dslowik@tellink.net> wrote:
>>>> u.get_all_permissions()
> set([u'wb.delete_libraryitem', u'wb.change_libraryitem'])
>>>> u.has_perm("wb.change_libraryitem")
> True
>
> ...Shouldn't that be False?

Why would it be False? get_all_permissions: Returns a set of
permission strings that the user has.... has_perm: Returns True if the
user has the specified permission.

https://docs.djangoproject.com/en/1.2/topics/auth/#django.contrib.auth.models.User.get_all_permissions

Re: Generating a list of available templates

2012-02-10T17:34:00.000-08:00

Thanks for the reply. Yes, this wouldn't be too tough if the directories in TEMPLATE_DIRS were all I had to worry about, but the glitch I mentioned earlier is that Django can also look for templates in places other than those listed explicitly in that setting.

For example, the template loader 'django.template.loaders.app_directories.Loader', which is enabled by default, looks for a "templates" directory within each one of your "installed apps." So a solution that only considers paths in TEMPLATE_DIRS would not work in that situation.

- Patrick

On Friday, February 10, 2012 at 5:05 PM, Bill Beal wrote:

I know nothing, but here's what I did:

python manage.py shell
import os
from settings import TEMPLATE_DIRS
for x in TEMPLATE_DIRS:
print x
os.listdir(x)

It gave me a list of the files in the (each) template directory.

It looks like you already have a list of template directories in settings.py.

User .get_all_permissions() vs. .has_perm() inconsistency

2012-02-10T16:01:00.000-08:00

Here is the code form my Python 2.6.6 session which is puzzling me:

>>> from django.contrib.auth.models import User
>>> u = User.objects.get(username='clint')
>>> u.get_all_permissions()
set([u'wb.delete_libraryitem', u'wb.change_libraryitem'])
>>> u.has_perm("wb.change_libraryitem")
True

...Shouldn't that be False?

I'm really trying to use permission checking as in:
{% if perms.foo.can_vote %}
as discussed in:
https://docs.djangoproject.com/en/1.2/topics/auth/#authentication-data-in-templates
, where I was expecting a False and got that True, but I've tracked
the problem down to the above puzzle.

I'm running
>>> django.VERSION
(1, 2, 3, 'final', 0)

Re: Generating a list of available templates

2012-02-10T14:15:00.000-08:00

Sorry... I think that's a little more complicated than what I need, actually. Django already handles searching for the template in all the right locations, so I don't have any problem actually rendering the template, and I shouldn't need to worry about absolute paths. Here's a simplified bit of code from the flatpage view in contrib.flatpages:

DEFAULT_TEMPLATE = 'flatpages/default.html'

def flatpage_detail(request, url):

# ...

f = get_object_or_404(FlatPage, url__exact=url)

if f.template_name:

t = loader.select_template((f.template_name, DEFAULT_TEMPLATE))

else:

t = loader.get_template(DEFAULT_TEMPLATE)

So in the Django admin site, if you have a flatpage that you want to use a template other than the default one, you enter the path to the template into the "template_name" field as something like 'flatpages/custom_template.html'. I want the exact same functionality, but I just want the admin site to display a select list of all templates in a given directory instead of a blank text field. So within my templates directory I'd make a directory at "flatpages/templates/" that includes "default.html," "custom_template_a.html," "custom_template_b.html" and so on.

I'm just stuck on how to generate a list of those templates to use as choices in the admin site select menu. I want the list to populate based on the actual files that exist in the directory and update itself when new files are added. When you save the model instance, the template name you selected is saved in a column on the model itself and rendering the correct template is no problem.

On Fri, Feb 10, 2012 at 4:54 PM, Python_Junkie <software.buy.design@gmail.com> wrote:

I think I just figured out what you want to do.

You want one drop down list with all of the templates listed
regardless of which folder the template lives in.

So, as describe above you would create a dictionary of template_names
by walking through the directories where the templates live
and pass the dictionary back to the drop down list.

Once the template is selected then you have to render back to the
folder that the selected template lives in.

You can create a database table with 2 columns , assuming all of the
templates are named uniquely.

column a contains the nameof all of the templates from the drop down
list.
column b contains the path that the template lives in.

So, when the user selects the template, the template value is passed
to the view.

The view can then perform a sql query

select template_path from table where template ='template_name'

value=crsr.fetchone()

full_path=value+template_name

render(full_path, plus whatever values you want to pass that
template)

If you don't want to use a table you could have python walk through
all of the directories until it achieves a match on the template name

I hope this solves your question

Re: Generating a list of available templates

2012-02-10T14:05:00.000-08:00

I know nothing, but here's what I did:

python manage.py shell

import os

from settings import TEMPLATE_DIRS

for x in TEMPLATE_DIRS:

print x

os.listdir(x)

It gave me a list of the files in the (each) template directory.

It looks like you already have a list of template directories in settings.py.

On Feb 10, 2012, at 4:51 PM, Patrick Wellever wrote:

Thanks -- you must be on your way out the door now so I won't call, but according to your area code it looks like we might be neighbors. ;) So following the syntax I wrote out, what I still need to know is how do I get to EVERY_DIRECTORY_DJANGO_LOOKS_FOR_TEMPLATES_IN. That's a variable that represents wishful thinking on my part -- I don't actually know how to get an iterable list of those directories.

There must be some way I can sort of hook into the logic Django uses to construct a list of template directories...

- P

On Fri, Feb 10, 2012 at 4:33 PM, Python_Junkie <software.buy.design@gmail.com> wrote:

I think you have it with the syntax you just wrote down.

I will be available by phone until 4:45 if you want to call.

781-...

On Feb 10, 4:19 pm, Patrick Wellever <pwelle...@gmail.com> wrote:
>
> I need something like:
>
> template_files = []
> for dir in EVERY_DIRECTORY_DJANGO_LOOKS_FOR_TEMPLATES_IN:
> template_files.extend(os.listdir(dir))

--
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Re: Generating a list of available templates

2012-02-10T13:54:00.001-08:00

I think I just figured out what you want to do.

You want one drop down list with all of the templates listed
regardless of which folder the template lives in.

So, as describe above you would create a dictionary of template_names
by walking through the directories where the templates live
and pass the dictionary back to the drop down list.

Once the template is selected then you have to render back to the
folder that the selected template lives in.

You can create a database table with 2 columns , assuming all of the
templates are named uniquely.

column a contains the nameof all of the templates from the drop down
list.
column b contains the path that the template lives in.

So, when the user selects the template, the template value is passed
to the view.

The view can then perform a sql query

select template_path from table where template ='template_name'

value=crsr.fetchone()

full_path=value+template_name

render(full_path, plus whatever values you want to pass that
template)

If you don't want to use a table you could have python walk through
all of the directories until it achieves a match on the template name

I hope this solves your question

On Feb 10, 4:33 pm, Python_Junkie <software.buy.des...@gmail.com>
wrote:
> I think you have it with the syntax you just wrote down.
>
> I will be available by phone until 4:45 if you want to call.
>
> 781-248-6557
>
> On Feb 10, 4:19 pm, Patrick Wellever <pwelle...@gmail.com> wrote:
>
>
>
>
>
>
>
> > Sorry, this question is turning out to be much more difficult to articulate
> > than I originally expected. Thanks for bearing with me. ;)
>
> > You definitely have the right idea of what I'm trying to do -- the only
> > problem with this method is that Django looks for templates in multiple
> > places, so I don't actually know the absolute path to the directory the
> > templates are in. You quoted the critical bit from the docs in your earlier
> > message: if 'django.template.loaders.app_directories.Loader' is included in
> > your TEMPLATE_LOADERS setting, Django will search for a directory called
> > 'templates' in each installed app, *in addition to all the directories
> > specified in TEMPLATE_DIRS*, when trying to load a template.
>
> > So if I have an app called 'myapp' and my settings.py contains this:
>
> > TEMPLATE_DIRS = ('/home/django/templates',)
>
> > TEMPLATE_LOADERS = (
> > 'django.template.loaders.filesystem.Loader',
> > 'django.template.loaders.app_directories.Loader',
> > )
>
> > ... then both "/home/django/templates/myapp/" and
> > "/path/to/myapp/templates/myapp/" are legitimate places to stick the
> > templates for the app. I'm trying to find a solution that would list the
> > contents of my specified directory in either of these locations.
>
> > I need something like:
>
> > template_files = []
> > for dir in EVERY_DIRECTORY_DJANGO_LOOKS_FOR_TEMPLATES_IN:
> > template_files.extend(os.listdir(dir))
>
> > I have to agree about the spoken word, though... Happy to discuss this by
> > phone if you'd like, and thanks again for your help.
>
> > - Patrick
>
> > On Fri, Feb 10, 2012 at 3:25 PM, Python_Junkie <
>
> > software.buy.des...@gmail.com> wrote:
> > > The internet is a wonderful invention, but sometimes the interchange
> > > of the spoken word is more efficient.
>
> > > Let's see if I have this straight.
>
> > > You know which directory the templates are in.
>
> > > 'templates/flatpages/page_templates/ for example.
> > > Is that correct?
>
> > > Then when you pass from the url.py to the specific view that you are
> > > directed to by the url you simply call the function
> > > *********************************************************
> > > files=os.listdir('templates/flatpages/page_templates/ ')
>
> > > template_qty=len(files)
>
> > > for xxx in range(template_qty):
> > > #####perform the logic to add values to the dictionary
> > > template_dictionary=( a:'a',b:'b') ### I forget the
> > > exact syntax
>
> > > render(form_template_listing.html,template_dictionary) - ## I
> > > forget the exact syntax
>
> > > ******************************************************
>
> > > Then in the form_template_listing.html , template unpack the template
> > > dictionary in the drop down list.
>
> > > I believe this is what you are asking.
>
> > > If not I can send you my cell phone number and we can discuss it.

Re: Generating a list of available templates

2012-02-10T13:51:00.000-08:00

Thanks -- you must be on your way out the door now so I won't call, but according to your area code it looks like we might be neighbors. ;) So following the syntax I wrote out, what I still need to know is how do I get to EVERY_DIRECTORY_DJANGO_LOOKS_FOR_TEMPLATES_IN. That's a variable that represents wishful thinking on my part -- I don't actually know how to get an iterable list of those directories.

There must be some way I can sort of hook into the logic Django uses to construct a list of template directories...

- P

On Fri, Feb 10, 2012 at 4:33 PM, Python_Junkie <software.buy.design@gmail.com> wrote:

I think you have it with the syntax you just wrote down.

I will be available by phone until 4:45 if you want to call.

781-...

On Feb 10, 4:19 pm, Patrick Wellever <pwelle...@gmail.com> wrote:
>
> I need something like:
>
> template_files = []
> for dir in EVERY_DIRECTORY_DJANGO_LOOKS_FOR_TEMPLATES_IN:
> template_files.extend(os.listdir(dir))

Re: Generating a list of available templates

2012-02-10T13:33:00.000-08:00

I think you have it with the syntax you just wrote down.

I will be available by phone until 4:45 if you want to call.

781-248-6557

On Feb 10, 4:19 pm, Patrick Wellever <pwelle...@gmail.com> wrote:
> Sorry, this question is turning out to be much more difficult to articulate
> than I originally expected. Thanks for bearing with me. ;)
>
> You definitely have the right idea of what I'm trying to do -- the only
> problem with this method is that Django looks for templates in multiple
> places, so I don't actually know the absolute path to the directory the
> templates are in. You quoted the critical bit from the docs in your earlier
> message: if 'django.template.loaders.app_directories.Loader' is included in
> your TEMPLATE_LOADERS setting, Django will search for a directory called
> 'templates' in each installed app, *in addition to all the directories
> specified in TEMPLATE_DIRS*, when trying to load a template.
>
> So if I have an app called 'myapp' and my settings.py contains this:
>
> TEMPLATE_DIRS = ('/home/django/templates',)
>
> TEMPLATE_LOADERS = (
> 'django.template.loaders.filesystem.Loader',
> 'django.template.loaders.app_directories.Loader',
> )
>
> ... then both "/home/django/templates/myapp/" and
> "/path/to/myapp/templates/myapp/" are legitimate places to stick the
> templates for the app. I'm trying to find a solution that would list the
> contents of my specified directory in either of these locations.
>
> I need something like:
>
> template_files = []
> for dir in EVERY_DIRECTORY_DJANGO_LOOKS_FOR_TEMPLATES_IN:
> template_files.extend(os.listdir(dir))
>
> I have to agree about the spoken word, though... Happy to discuss this by
> phone if you'd like, and thanks again for your help.
>
> - Patrick
>
> On Fri, Feb 10, 2012 at 3:25 PM, Python_Junkie <
>
>
>
>
>
>
>
> software.buy.des...@gmail.com> wrote:
> > The internet is a wonderful invention, but sometimes the interchange
> > of the spoken word is more efficient.
>
> > Let's see if I have this straight.
>
> > You know which directory the templates are in.
>
> > 'templates/flatpages/page_templates/ for example.
> > Is that correct?
>
> > Then when you pass from the url.py to the specific view that you are
> > directed to by the url you simply call the function
> > *********************************************************
> > files=os.listdir('templates/flatpages/page_templates/ ')
>
> > template_qty=len(files)
>
> > for xxx in range(template_qty):
> > #####perform the logic to add values to the dictionary
> > template_dictionary=( a:'a',b:'b') ### I forget the
> > exact syntax
>
> > render(form_template_listing.html,template_dictionary) - ## I
> > forget the exact syntax
>
> > ******************************************************
>
> > Then in the form_template_listing.html , template unpack the template
> > dictionary in the drop down list.
>
> > I believe this is what you are asking.
>
> > If not I can send you my cell phone number and we can discuss it.

Re: Generating a list of available templates

2012-02-10T13:19:00.001-08:00

Sorry, this question is turning out to be much more difficult to articulate than I originally expected. Thanks for bearing with me. ;)

You definitely have the right idea of what I'm trying to do -- the only problem with this method is that Django looks for templates in multiple places, so I don't actually know the absolute path to the directory the templates are in. You quoted the critical bit from the docs in your earlier message: if 'django.template.loaders.app_directories.Loader' is included in your TEMPLATE_LOADERS setting, Django will search for a directory called 'templates' in each installed app, in addition to all the directories specified in TEMPLATE_DIRS, when trying to load a template.

So if I have an app called 'myapp' and my settings.py contains this:

TEMPLATE_DIRS = ('/home/django/templates',)

TEMPLATE_LOADERS = (
'django.template.loaders.filesystem.Loader',
'django.template.loaders.app_directories.Loader',
)

... then both "/home/django/templates/myapp/" and "/path/to/myapp/templates/myapp/" are legitimate places to stick the templates for the app. I'm trying to find a solution that would list the contents of my specified directory in either of these locations.

I need something like:

template_files = []

for dir in EVERY_DIRECTORY_DJANGO_LOOKS_FOR_TEMPLATES_IN:

template_files.extend(os.listdir(dir))

I have to agree about the spoken word, though... Happy to discuss this by phone if you'd like, and thanks again for your help.

- Patrick

On Fri, Feb 10, 2012 at 3:25 PM, Python_Junkie <software.buy.design@gmail.com> wrote:

The internet is a wonderful invention, but sometimes the interchange
of the spoken word is more efficient.

Let's see if I have this straight.

You know which directory the templates are in.

'templates/flatpages/page_templates/ for example.
Is that correct?

Then when you pass from the url.py to the specific view that you are
directed to by the url you simply call the function
*********************************************************
files=os.listdir('templates/flatpages/page_templates/ ')

template_qty=len(files)

for xxx in range(template_qty):
#####perform the logic to add values to the dictionary
template_dictionary=( a:'a',b:'b') ### I forget the
exact syntax

render(form_template_listing.html,template_dictionary) - ## I
forget the exact syntax

******************************************************

Then in the form_template_listing.html , template unpack the template
dictionary in the drop down list.

I believe this is what you are asking.

If not I can send you my cell phone number and we can discuss it.

Re: Generating a list of available templates

2012-02-10T12:25:00.001-08:00

The internet is a wonderful invention, but sometimes the interchange
of the spoken word is more efficient.

Let's see if I have this straight.

You know which directory the templates are in.

'templates/flatpages/page_templates/ for example.
Is that correct?

Then when you pass from the url.py to the specific view that you are
directed to by the url you simply call the function
*********************************************************
files=os.listdir('templates/flatpages/page_templates/ ')

template_qty=len(files)

for xxx in range(template_qty):
#####perform the logic to add values to the dictionary
template_dictionary=( a:'a',b:'b') ### I forget the
exact syntax

render(form_template_listing.html,template_dictionary) - ## I
forget the exact syntax

******************************************************

Then in the form_template_listing.html , template unpack the template
dictionary in the drop down list.

I believe this is what you are asking.

If not I can send you my cell phone number and we can discuss it.

On Feb 10, 3:01 pm, "Demetrio Girardi" <demetrio.gira...@gmail.com>
wrote:
> On 10 Feb 2012 at 14:50, Patrick Wellever wrote:
>
> > I want to make it a choice field that justs lists all the files in, for example,
> > 'templates/flatpages/page_templates/', so the user can see what templates are available and just
> > choose one from a select list.
>
> you can read the filesystem in the form's (or form field's) __init__.

Re: Generating a list of available templates

2012-02-10T12:01:00.000-08:00

On 10 Feb 2012 at 14:50, Patrick Wellever wrote:

> I want to make it a choice field that justs lists all the files in, for example,
> 'templates/flatpages/page_templates/', so the user can see what templates are available and just
> choose one from a select list.

you can read the filesystem in the form's (or form field's) __init__.

Re: Generating a list of available templates

2012-02-10T11:50:00.000-08:00

Sorry to be unclear... Basically the functionality I want is just like in contrib.flatpages -- the model has a field called 'template' that allows the user to specify an alternate template for the object detail page. But in the flatpages app, the field is just a charfield, so the user has to know which templates are available, then enter something like 'flatpages/some_template.hrml' in the field.

I want to make it a choice field that justs lists all the files in, for example, 'templates/flatpages/page_templates/', so the user can see what templates are available and just choose one from a select list.

Don't need to create templates dynamically or store them in the db.

Thanks for your patience.

Patrick

On Feb 10, 2012 2:00 PM, Python_Junkie <software.buy.design@gmail.com> wrote:

I am not sure that I follow you.

When you mention creating new templates (you would be creating these
dynamically?) and have them show up in your database (model?)

Please explain or provide an example

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