Interpolation and comparation between 2 dates: easy and difficult at the same time

I've develope a "simple" function to calculate the difference between 2 dates, and the time that they are interpolated.

I need it to: I arrive to a site at a hour (my_from), I go out from the site at a hour (my_to). Some friend arrive at the site at a hour (his_from) and let it at a hour (his_to)

If I stay in the site after he arrives and before he goes out, the "probability" of match is 1, if I let the site after he arrives, the probability of match is 0... You can see the samples in the documentation.

I need to know if this is a good way to do, and if compare all the kinds of matching (I've found 6). This is the code:

    def time_match(self, my_from, my_to, his_from, his_to):

        """

            I've found 6 general kinds of time matching. It's better to explain it with graphics:

              (my_from)--A--(my_to)

            -------------------------

             (his_from)--B--(his_to)

        """

        #    |-A-|                           |-A-|

        # -------------------- or --------------------

        #           |--B--|        |--B--|

        if my_to < his_from or his_to < my_from:

            return 0

        #      |--A--|

        # --------------------

        #  |------B-------|

        elif my_from >= his_from and my_to <= his_to:

            return 1

        #    |-----A-------|

        # --------------------

        #        |-B-|

        elif my_from < his_from and my_to > his_to:

            my_diff_to_reuse = diff_in_seconds(my_from, my_to)

            diff = my_diff_to_reuse - self.diff_in_seconds(his_from, his_to)

            return (diff / my_diff_to_reuse)

        #   |---A---|

        # --------------------

        #       |---B---|

        elif my_from <= his_from and my_to <= his_to:

            diff = self.diff_in_seconds(his_from, my_to)

            return (diff / self.diff_in_seconds(my_from, my_to))

        #         |---A---|

        # --------------------

        #    |---B---|

        elif my_from >= his_from and my_to >= his_to:

            diff  = self.diff_in_seconds(my_from, his_to)

            return (diff / self.diff_in_seconds(my_from, my_to))

        # If I'm here I have a problem

        return 0

    def diff_in_seconds(date1, date2):

        # Initial from: http://www.bytemycode.com/snippets/snippet/304/

        timedelta = date2 - date1

        diff = timedelta.days*24*3600 + timedelta.seconds

        return abs(float(diff))

Thanks!

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