Re: example for project with user login

You can watch my code: 

https://github.com/jelukas/django-usuarios-framework/

I am using django-registration with templates.

And django 1.4 .. i have to update the code to django 1.5 but it is the same idea.

Jesús Lucas Flores | Sysadmin, Web Developer and IT Startups Lover

 es.linkedin.com/in/jesuslucas

 github.com/jelukas

 @jelukas89 

 Skype: jelukas89

2013/9/27 Rafael E. Ferrero <rafael.ferrero@gmail.com>

in settings.py

in TEMPLATE_DIRS put all your templates folders where django go to find them

in MIDDLEWARE_CLASSES = (
    'django.middleware.common.CommonMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
 )

in INSTALLED_APPS = (
    'django.contrib.auth',  #important to login and logout
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.sites',
    'django.contrib.messages',
    'django.contrib.staticfiles',
    'django.contrib.admin',
    'YourProject.YourApp',
)

and create this
LOGIN_URL = '/url/to/login/'
LOGOUT_URL = '/url/to/logout/'
LOGIN_REDIRECT_URL = '/url/to/your/view'

in your general urls.py

from django.contrib.auth.views import login, logout_then_login
from django.conf.urls.defaults import patterns, url, include
from django.conf import settings
 
from django.contrib import admin
admin.autodiscover()
 
urlpatterns = patterns('',
    (r'^YourApp/', include('YourProject.YourApp.urls')),
    (r'^login/$', login, {'template_name': 'login.djhtml'}),
    (r'^logout/$', logout_then_login),

    # For admin

    url(r'^admin/', include(admin.site.urls)),
)
 
if settings.DEBUG:
    urlpatterns += patterns('',
        url(r'^media/(?P<path>.*)$', 'django.views.static.serve', {
            'document_root': settings.MEDIA_ROOT,
        }),
   )

in YourApp/urls.py
from django.conf.urls.defaults import patterns, url
 
urlpatterns = patterns('YourProject.YourApp.views',
    url(r'^$', 'YourViewName'),
)

need a base.djhtml in YourTemplateFolder
in YourTemplateFolder/login.djhtml

{% extends "base.djhtml" %}
{% block cuerpo %}
    {% if form.errors %}
       <p>Su nombre de usuario y contraseña no coinciden. Por favor intente nuevamente.</p>
    {% endif %}       
    <form method="post" action="">
    {% csrf_token %}               
        <label>Nombre de Usuario</label><input id="id_username" type="text" name="username" maxlength="30" /><br />
        <label>Clave de Usuario</label><input type="password" name="password" id="id_password" /><br />               
        <input type="submit" value="login" />
        <input type="hidden" name="next" value="{{ next }}" />
    </form>
{% endblock %}

in your YourApp/views.py

from django.contrib.auth.decorators import login_required
from django.template.context import RequestContext

@login_required
def yourViewName(Request):

    #your code here
    return render_to_response('yourTemplate', {'YourDict': yourDict},
                              context_instance=RequestContext(Request))

I think that something like that will work, its copy of a small project mine in django 1.3.1, its admin somewher ther but you can eliminate. (in www.fsorgosuardi.com.ar/dj/login its this code running... to see the site just go to www.fsorgosuardi.com.ar)

you can, later, try with allauth app... its really cool stuff

2013/9/27 Joachim Wuttke <j1wuttke@gmail.com>

With user login to the user views.
I would like to build my application by incrementally modifying a working small application
that is just a little more complete than the poll application from the basic tutorial.

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Rafael E. Ferrero

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