Building a search form with 4 required choices, which will be inserted as arguments in an URL [warning: long question]

This is a semi-long question.  Please let me know wherever I make a mistake.

I'm building a search form with 4 required choices, 1 of the choices is a CharField with a max_length of 3.  The other 3 choices are ChoiceField's.  Here is a picture of what the search form looks like:

I've read through the Django docs and other things on the Internet but I'm still very unclear about how to approach this.

1. First I believe I need to create 4 args or kwargs in the url for each of the choices.  If I use args, it would look something like...

url(r'^search?(\w+{3})&(\w+{2})&(\w+{1-2})&(\w+{1-2})', function/class view, name='search')

2. Next, I need to pass the user's input in the html page into the url args.  I have a form set up to get the user's input.  But how would I write this on the HTML page?  Do I simply make a url tag like {% url 'search' args1, args2, args3, args4 %}?

3. Then I need to create the views function.  My first question is, should I use a function-based view or the generic class-based ListView?  The result of the search will be a list of items, so ListView is a good template to use, but I don't know how having 4 args would affect using ListView.  My second question is, what is the most effective way of making this search?  I need to check if any records in the database matches the user's search, so would I do something like 'For record in database' to check over every record in the database?

If I used a function view, would it look something like:

def search(request, args1, args2, args3, args4):

     for record in database:

          if args matches record:

               display record

Thank you for reading through the question

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