My initial recommendation would be to read up on the Forms section of the Django manual.
A lot of the logic you've written here is abstracted away in Django's built-in methods.
Also, I'd replace that messy HTML in views.py with a call to a separate partial.
In fact, that partial would probably being in a form from your forms.py.
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Sincerely,
Thomas Murphy
646.957.6115
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I am a newbie. I am learning Django by developing a web application. There is use-case where I got stuck.--there are 3 buttons on a html pagePersonal infoEducationWork ExperienceIt is desired when the user click any of the button, respective html form shall be displayed on right-half of web-page.What I have tried is this, onclick function of buttons:function myfun(){var xmlhttp;if (window.XMLHttpRequest){xmlhttp=new XMLHttpRequest();}else{xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");}xmlhttp.onreadystatechange=function(){if (xmlhttp.readyState==4 && xmlhttp.status==200){document.getElementById("rightpan").innerHTML=xmlhttp.responseText;}}xmlhttp.open("GET","{% url "polls:demo_test" %}",true);xmlhttp.send();}</script>in views.py, demo test does this:def demo_test(request):return HttpResponse("<form name='reg' onsubmit='return ValidateForm(this)' action='{% url 'polls:signupexec' %}' method='post'><tr><td><div>Firstname:</div></td><td><input type='text' name='first_name' /></td></tr><tr><td><div>Lastname:</div></td><td><input type='text' name='last_name' /></td></tr><tr><td><input name='submit' type='submit' value='Submit' /></td></tr></form>")Please give some suggestions on how can I do this. Loading HTML Forms dynamically through AJAX.
- First of all, it works fine except that it does not embed CSRF_TOKEN in the form, which is important.
- Secondly, I feel that this approach is against the philosophy of django.
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