Re: Best way to use a 'all' QuerySet as a dict with id first

@James Brewer:
If I change my code, I can have this user_ids list.
btw, it's filter and not get if you're searching multiple objects (the
user_ids).

@Alejandro Varas G.:
That doesn't change the fact that 'User.objects.get(id=X)' will hit the
database everytime.

Right now, the problem is solved, by creating the AllUserSet, but I think my
code is pretty ugly, and it seems strange to me that the ORM can't handle that
built-in, by caching the .all() or .filter(id__in=users_ids)

The ideally solution would be something like:

AllUser = User.objects.all()

for i in user_id:
AllUser.get(id=i)

But this code hits the database every time the 'get' is called.


On 26/09/14 12:36, James Brewer wrote:
> Do you have a single list of the IDs you want? If so, you can do something
> like `User.objects.get(id__in=user_ids)`. This will fetch all Users whose
> `id` is in some list `user_ids`.
>
> Does that help?
>
> Happy hacking!
>
> James
>
> On Fri, Sep 26, 2014 at 11:43 AM, Alejandro Varas G. <alej0varas@gmail.com>
> wrote:
>
> > Hi,
> >
> > You should use User.objects.get(id=X)
> >
> > Best
> > El 26/09/2014 15:28, "aRkadeFR" <contact@arkade.info> escribió:
> >
> > >
> > > Hey!
> > >
> > > I'm having a hard time trying to reduce the number of SQL queries on a
> > view.
> > >
> > > Basically, I'm fetching all my User, with User.objects.all(), and save
> > this
> > > queryset as AllUser.
> > >
> > > Then every time I need to get the user with the id = X , I'm calling a
> > function
> > > 'get_user_from_id', that iterate over the AllUser queryset variable, and
> > when
> > > it finds the id, returns it.
> > >
> > > I considerably reduced the number of SQL queries, but I would like to
> > know if
> > > you think of a better way?
> > >
> > > Thank you
> > >
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> --
> James Brewer
> jamesbrewer.io
>
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