I just found out on Django document, there's an example that's for manytomany, using 'through' when defining the foreign key. I think this is what i need.
On Wednesday, June 21, 2017 at 2:49:40 PM UTC-7, Kevin Yu wrote:
-- Here's the example:
from django.db import models
class Person(models.Model):
name = models.CharField(max_length=128)
def __str__(self): # __unicode__ on Python 2
return self.name
class Group(models.Model):
name = models.CharField(max_length=128)
members = models.ManyToManyField(Person, through='Membership')
def __str__(self): # __unicode__ on Python 2
return self.name
class Membership(models.Model):
person = models.ForeignKey(Person, on_delete=models.CASCADE)
group = models.ForeignKey(Group, on_delete=models.CASCADE)
date_joined = models.DateField()
invite_reason = models.CharField(max_length=64)
On Wednesday, June 21, 2017 at 2:49:40 PM UTC-7, Kevin Yu wrote:
I'm working with a legacy database so I have to set managed=False in the model. Here's the 3 related tables:class Branches(models.Model):name = models.CharField(max_length=128) branchpoint_str = models.CharField(max_length=255) dev_lead_id = models.IntegerField(blank=True, null=True) source = models.CharField(max_length=255) state = models.CharField(max_length=255) kind = models.CharField(max_length=255) desc = models.TextField(blank=True, null=True)approved = models.IntegerField()for_customer = models.IntegerField()deactivated_at = models.DateTimeField(blank=True, null=True) created_at = models.DateTimeField(blank=True, null=True) updated_at = models.DateTimeField(blank=True, null=True) codb_id = models.IntegerField(blank=True, null=True) pm_lead_id = models.IntegerField(blank=True, null=True) version = models.CharField(max_length=20, blank=True, null=True) path_id = models.IntegerField(blank=True, null=True) branchpoint_type = models.CharField(max_length=255, blank=True, null=True) branchpoint_id = models.IntegerField(blank=True, null=True) class Meta:managed = Falsedb_table = 'branches'verbose_name_plural = 'Branches'class Projects(models.Model):id = models.AutoField(primary_key=True) name = models.CharField(max_length=40, primary_key=True) status = models.CharField(max_length=255) platform = models.CharField(max_length=255) enabled = models.IntegerField()path = models.CharField(max_length=128, blank=True, null=True) tag_prefix = models.CharField(max_length=64, blank=True, null=True) created_at = models.DateTimeField(blank=True, null=True) updated_at = models.DateTimeField(blank=True, null=True) codb_id = models.IntegerField(blank=True, null=True) template = models.CharField(max_length=64, blank=True, null=True) image_path = models.CharField(max_length=128, blank=True, null=True) repository_id = models.IntegerField(blank=True, null=True) number_scheme = models.CharField(max_length=32) special_dir = models.CharField(max_length=32, blank=True, null=True) project_family_id = models.IntegerField()class Meta:managed = Falsedb_table = 'projects'verbose_name_plural = 'projects'class BranchesProjects(models.Model): # project_id = models.IntegerField()# branch_id = models.IntegerField()project = models.ForeignKey(Projects, on_delete=models.CASCADE)branch = models.ForeignKey(Branches, on_delete=models.CASCADE)class Meta:managed = Falsedb_table = 'branches_projects'
I have been able to do the join using raw(). However, the return object is rawqueryset. What I want is queryset so that I can use django-filter to process it. My current raw sql is like this:
My question is, is there a way to achieve the same result using Django's queryset? I've also explored the idea of using the extra() in django extra but it doesn't really work for me.
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