Re: Django Templates and Conditional CSS classes

Hi treyd, 

I think idea of updating the model and storing it in the db is a bit overkill, however you could create an @propery on the model that will do that logic for you and return the css class for you.

e.g.

@property

def css_class(self):

  if self.state is SUCHANDSUCH:

     return "label-soandso"

and so in the template you can do what Vijay recommended but without storing anything you don't need in the database.

Good luck with going Angular, it plays well with Django! 

On Saturday, 11 November 2017 09:50:38 UTC+11, treyd wrote:

Thanks, all, for the info.  Looks like the best way to clean this up is to make the model have some knowledge of the CSS class I want to use and make a method to get it.  I like that, but I was unsure about sticking view information into the model.  Probably the best solution is javascript logic in the browser, which I'll get to.

On Friday, November 10, 2017 at 5:45:02 PM UTC-5, Vijay Khemlani wrote:

You can also add a "state_css_class" (or something) method to your object class and just call

<span class="label {{ myobject.state_css_class  }}">...</span>

the method should be quite simple

On Fri, Nov 10, 2017 at 7:01 PM, Adam Simon <add.si...@gmail.com> wrote:

 You can pass the class from either the model or the view into the template. For example, you can assign a class to a button with a variable:

<button class="{{ class }}"><|button>

And then the class would have to be defined in your style somewhere

On Fri, Nov 10, 2017 at 1:37 PM treyd <tr...@treyd.us> wrote:

At some point I plan on figuring out how to do more intelligent front-end in-browser stuff (Angular, etc) which yeah would definitely help me here but I was wondering if there was a Django-only way of doing this.

On Friday, November 10, 2017 at 3:51:09 PM UTC-5, Adam wrote:

Are you open to using JavaScript in the front end? It would make it really easy

On Fri, Nov 10, 2017 at 12:40 PM treyd <tr...@treyd.us> wrote:

Hello,

I am trying to render a model field in a django template, and, based on the value of the field, I want to specify a different CSS class.  Right now, my solution is this:

<span class="label {% if myobject.state == 'Scheduled' %}label-default
                   {% elif myobject.state == 'Provisioning' %}label-primary
                   {% elif myobject.state == 'Active' %}label-success
                   {% elif myobject.state == 'Deleting' %}label-primary
                   {% elif myobject.state == 'Ended' %}label-info
                   {% endif %}">{{ myobject.state }}</span>

This works, but seems like a really ugly solution and a bunch of logic in the template.  Is there a better way of doing this?  My thought was to put the class names as another field in the model, but that seems like it would violate the MVC (or MVT) separation. Any ideas?

Thanks in advance,

treyd

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