Re: Select all users that have undone jobs (select, groupby, count)

I think the best way is to create a custom manager for the job (check
the documentation for details-managers). In the manager, do a query
that gets all the users with undone jobs by using the filter option
(also see the documentation - making queries). From the resulting
querydict you could count the occurrence of each unique user in the
querydict to form your dictionary. This could be potentially
inefficient so make sure you save the first query in a variable and
work with that variable.

Meanwhile someone else might know a less verbose way to do it.

On 8/29/11, muzhig <arseniy.potapov@gmail.com> wrote:
> Hello!
> I have model Job, that is linked to User.
> Job has flag `done` that indicates progress of this job.
>
> How to select list of all users, that have undone jobs, annotated by count
> of this undone jobs?
>
> I need this dict: { user1: 4, user2:12 .... }
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To view this discussion on the web visit
> https://groups.google.com/d/msg/django-users/-/948LTdoWGq4J.
> To post to this group, send email to django-users@googlegroups.com.
> To unsubscribe from this group, send email to
> django-users+unsubscribe@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/django-users?hl=en.
>
>

--
Sent from my mobile device

--
You received this message because you are subscribed to the Google Groups "Django users" group.
To post to this group, send email to django-users@googlegroups.com.
To unsubscribe from this group, send email to django-users+unsubscribe@googlegroups.com.
For more options, visit this group at http://groups.google.com/group/django-users?hl=en.