Re: how to call django web page with ordinary html page

If it helps, you can read/set the csrf cookie using javascript. here's some rough code:

  if(!document.cookie.match('csrftoken=([a-zA-Z0-9]{32})')){
    for(var c = ''; c.length < 32;) c += Math.random().toString(36).substr(2, 1)
    document.cookie = 'csrftoken=' + c + '; path=/'
  }
  document.write('<input type="hidden" name="csrfmiddlewaretoken" value="' + document.cookie.match('csrftoken=([a-zA-Z0-9]{32})')[1] + '">')

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Re: Django framework plugin

All you need to do is make sure the directory containing "Djangowork" is on the python path, then just add "Djangowork" to the INSTALLED_APPS of a different project.

see here for more info: https://docs.djangoproject.com/en/dev/intro/reusable-apps/

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Re: response to ajax (jquery) with variables

Hi again Antonio,

First of all, make sure you are using a good browser with debugging capabilities (I prefer Chrome), because you'll need it.

Secondly, I usually use the $.ajax request, instead of the post. Mainly because post is a wrapper around ajax and you can more finely change the settings of ajax.

So the post in your case would be:

$.ajax({

    type: 'POST',               // Make sure you post

    dataType: 'json',          // Use this so that you request json from the server

    url: "/sitioweb/json/",

    data: data,

    success: function(data) {

        // The data that is returned is your json data, already parser, so you don't have to parse it!

        alert(data.array[0]);     // Need to write "array" because that is what you are sending to the browser (your structure looks like that, check what the server is responding with)

    },

    error: function(xhr, textStatus, errorThrown) {

        console.log('AJAX communication failed:', textStatus, errorThrown);    // In case there is an error (for example a 500)

    }

});

Regards,

Andréas

2014-08-30 4:57 GMT+02:00 Antonio Russoniello <arussoni@musicparticles.com>:

Now I can read data from  ajax to my def but I have not idea to how send, for examle, an array to jquery and manage this from javascript...

I tried:

def json_prueba(request):
    arrg = [1,2,3,4]
    if request.method == 'POST':
        return HttpResponse(simplejson.dumps({'array': arrg}), content_type="application/json")
    return HttpResponse('FAIL!!!!!')

from the page side:

    function updateDB(){
        $.post("/sitioweb/json/", data, function(response){
            if(response){
                var data = JSON.parse(response); <--------- NOT SURE IF THIS IS CORRECT
                alert(data[0]); }              <----- I´m trying to put on an alert windows the first item of my array arrg
            else{ alert('Error! :(');}
        });
    }

Thanks in advande.

AR

El 28/08/2014 02:57 a.m., Andreas Kuhne escribió:

Hi Antonio,

import simplejson as json

return HttpResponse(

    json.dumps({

        'array': example

    }),

    content_type="application/json"

)

That would do the trick. This is returned as JSON. Remember to set the content_type, otherwise the client can get confused.

Regards,

Andréas

2014-08-28 2:56 GMT+02:00 Antonio Russoniello <arussoni@musicparticles.com>:

Hello,

i hope you can help me with this, I'm trying to send to an ajax (jquery from my html template) a response but i would like to send also a new variable.

in my html template I have:

    $("#init_date").click(function(){
        var some_date = {'init_date': init_date, 'end_date': end_date};
        $.post("/filter_dates/", some_date, function(response){
            if(response === 'success'){
                MAKE SOMETHING!!!
            else{ alert('error'); }
        });
    });

my django view look like:

def filter_date(request):
    if request.method == 'POST':
        example = ['A','B','C']
        init_date = request.POST['init_date']
        end_date = request.POST['end_date']
         MAKE SOMETHING!!
        return HttpResponse('success') AND HERE I WOULD LIKE TO SEND THE example ARRAY...
    else:
        return HttpResponse('error')

How can I send the array o some other variable as response?

Regards,
AR

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Re: how to call django web page with ordinary html page

On 30 Aug 2014 07:15, "James Schneider" <jrschneider83@gmail.com> wrote:
>
> I reread the OP, and it sounds like he is using a static HTML page served elsewhere and POSTing directly to the Django app. If you disable CSRF validation on the form view in Django, it should work. However, I would recommend against it.
>
> Unless you have a specific reason, why not just write up a quick TemplateView (with CSRF disabled on the FormView) or better yet a straight FormView class and just render the exact HTML you posted with the CSRF tag, taking advantage of the benefits that the Django framework offers?
>
> -James
>

This is exactly where i was going.
>
> On Friday, August 29, 2014, Pawan Soni <pawan.soni410@gmail.com> wrote:
>>
>>
>>
>> On Friday, August 29, 2014 5:47:19 PM UTC+5:30, Shubham Pansari wrote:
>>>
>>> You are missing csrf_token which is set by request for csrf verification. After the line
>>> <form action="http://127.0.0.1:8000/test/" method="post">
>>> in your code put {%csrf_token%} and it should work fine and also read why it didnot worked without it from https://docs.djangoproject.com/en/dev/ref/contrib/csrf/  . This should answer all your queries.
>>>
>>>
>>> On Fri, Aug 29, 2014 at 4:36 PM, Pawan Soni <pawan....@gmail.com> wrote:
>>>>
>>>> Hi ,
>>>>
>>>> i have a simple html page,p.html which is not made in django application ,its just a ordinary html page  which look like..
>>>>
>>>> <html>
>>>> <body>
>>>> <form action="http://127.0.0.1:8000/test/" method="post">
>>>> <input type="text" value="test" name="payemnt_ref">
>>>> <input type="submit">
>>>> </body>
>>>> <html>
>>>>
>>>> In form's action i am passing the path of my django url..
>>>>
>>>> this is my urls.py file..
>>>>
>>>>          from django.conf.urls import patterns, include, url
>>>>         from django.contrib import admin
>>>>         from login import views
>>>>               urlpatterns = patterns('',
>>>>            url(r'^test',views.paymentcheck_view,name="test"),
>>>>    )
>>>>
>>>> my views.py..
>>>>     
>>>>      def paymentcheck_view(request):
>>>>    if request.method == "POST":
>>>>         c = {}
>>>>         c.update(csrf(request))
>>>>         return render_to_response('login1/create_pay_page.html',c)
>>>>    else:
>>>>         return HttpResponse('GET')
>>>>
>>>> Error i got ...
>>>>
>>>> Forbidden (403)
>>>>
>>>> CSRF verification failed. Request aborted.
>>>>
>>>> ........
>>>>     
>>>> i am stuck over here,pls help me 
>>>>
>>>> Thnx in advance
>>>>
>>>>
>>>> ____________________________________________________________________
>>
>>              Thanks Shubham for guiding me and your precious response,but my concern is that if i used simple/plain html page and if i would use {%csrf_token %} in that page ,i think this is not working .

Did you actually try it?

>>               Is any other alternative ways to do this task.
>>     Thanks :)
>>
>>
>>   
>>>>
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>>>
>>>
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Re: how to call django web page with ordinary html page

I reread the OP, and it sounds like he is using a static HTML page served elsewhere and POSTing directly to the Django app. If you disable CSRF validation on the form view in Django, it should work. However, I would recommend against it.

Unless you have a specific reason, why not just write up a quick TemplateView (with CSRF disabled on the FormView) or better yet a straight FormView class and just render the exact HTML you posted with the CSRF tag, taking advantage of the benefits that the Django framework offers?

-James

On Friday, August 29, 2014, Pawan Soni <pawan.soni410@gmail.com> wrote:

On Friday, August 29, 2014 5:47:19 PM UTC+5:30, Shubham Pansari wrote:

You are missing csrf_token which is set by request for csrf verification. After the line
<form action="http://127.0.0.1:8000/test/" method="post">

in your code put {%csrf_token%} and it should work fine and also read why it didnot worked without it from https://docs.djangoproject.com/en/dev/ref/contrib/csrf/  . This should answer all your queries.

On Fri, Aug 29, 2014 at 4:36 PM, Pawan Soni <pawan....@gmail.com> wrote:

Hi ,

i have a simple html page,p.html which is not made in django application ,its just a ordinary html page  which look like..

<html>

<body>

<form action="http://127.0.0.1:8000/test/" method="post">

<input type="text" value="test" name="payemnt_ref">

<input type="submit">

</body>

<html>

In form's action i am passing the path of my django url..

this is my urls.py file..

         from django.conf.urls import patterns, include, url

        from django.contrib import admin

        from login import views

              urlpatterns = patterns('',

           url(r'^test',views.paymentcheck_view,name="test"),

   )

my views.py..

    

     def paymentcheck_view(request):

   if request.method == "POST":

        c = {}

        c.update(csrf(request))

        return render_to_response('login1/create_pay_page.html',c)

   else:

        return HttpResponse('GET')

Error i got ...

Forbidden (403)

CSRF verification failed. Request aborted.

........

    

i am stuck over here,pls help me 

Thnx in advance

____________________________________________________________________

             Thanks Shubham for guiding me and your precious response,but my concern is that if i used simple/plain html page and if i would use {%csrf_token %} in that page ,i think this is not working .

              Is any other alternative ways to do this task.

    Thanks :)

  

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Re: how to call django web page with ordinary html page

On Friday, August 29, 2014 5:47:19 PM UTC+5:30, Shubham Pansari wrote:

You are missing csrf_token which is set by request for csrf verification. After the line
<form action="http://127.0.0.1:8000/test/" method="post">

in your code put {%csrf_token%} and it should work fine and also read why it didnot worked without it from https://docs.djangoproject.com/en/dev/ref/contrib/csrf/  . This should answer all your queries.

On Fri, Aug 29, 2014 at 4:36 PM, Pawan Soni <pawan....@gmail.com> wrote:

Hi ,

i have a simple html page,p.html which is not made in django application ,its just a ordinary html page  which look like..

<html>

<body>

<form action="http://127.0.0.1:8000/test/" method="post">

<input type="text" value="test" name="payemnt_ref">

<input type="submit">

</body>

<html>

In form's action i am passing the path of my django url..

this is my urls.py file..

         from django.conf.urls import patterns, include, url

        from django.contrib import admin

        from login import views

              urlpatterns = patterns('',

           url(r'^test',views.paymentcheck_view,name="test"),

   )

my views.py..

    

     def paymentcheck_view(request):

   if request.method == "POST":

        c = {}

        c.update(csrf(request))

        return render_to_response('login1/create_pay_page.html',c)

   else:

        return HttpResponse('GET')

Error i got ...

Forbidden (403)

CSRF verification failed. Request aborted.

........

    

i am stuck over here,pls help me 

Thnx in advance

____________________________________________________________________

             Thanks Shubham for guiding me and your precious response,but my concern is that if i used simple/plain html page and if i would use {%csrf_token %} in that page ,i think this is not working .

              Is any other alternative ways to do this task.

    Thanks :)

  

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Re: related_query_name - what is it?

No problem.

I think I also found how to deal with M instances which are not related to R (R instances have foreign key to M). I tried M.filter(related_query_name_from_R__isnull=False) and it seems to work.

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