Re: Onchange event on Choicefield in django formset

I think your 'answer' is going to exist in POST in either case. Perhaps change the construct of your logic to:

    if 'evaluation' in request.POST:

        return render_to_response('results.html')

    elif 'form-0-answer' in request.POST:
        answer = request.POST.get('answer','')
        values.append(answer)
        return render_to_response('success.html')

Furbeenator

On Wed, Nov 2, 2011 at 9:21 AM, Kurtis Mullins <kurtis.mullins@gmail.com> wrote:

Try changing your success_url to this same page.

On Wed, Nov 2, 2011 at 11:00 AM, asif.jamadar@rezayat.net <asif.jamadar@rezayat.net> wrote:

How can i access the form fields in django views.

Suppose i have modelform called


class QuestionForm(forms.ModelForm):


 answer = forms.ChoiceField(choices=HAY_EVALUATION_CHOICES,

widget=forms.Select(attrs={'onchange': 'this.form.submit();'}))


In views.py


     if 'form-0-answer' in request.POST:


       answer = request.POST.get('answer','')


       values.append(answer)


       return render_to_response('success.html')


    if 'evaluation' in request.POST:

        return render_to_response('results.html')

The form consist of one submit button called 'evaluation' and second
is having onchange event on selection

Here i'm trying to perform some operation on selection, then by using
second button that is 'evaluation' i will save the form.

Here the problem is the form is always redirecting to success.html
even when i click 'evaluation' button



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