Re: PIL issue opening an image file

Well, Bruno, if I knew exactly how to solve this I wouldn't be sitting here taking your snooty remarks, would I? I am asking because I do not know how to go about it.

On Fri, Nov 26, 2010 at 4:50 PM, bruno desthuilliers <bruno.desthuilliers@gmail.com> wrote:

On 26 nov, 15:03, Sithembewena Lloyd Dube <zebr...@gmail.com> wrote:
> I found the issue: it is the path to the image. When I change the problem
> line to
>
> image = Image.open(os.path.realpath('C:\Users\Lloyd\Desktop\Lloyd.png'))
>
> it works,

Well, kinda... accidentally...

> but I cannot hard code the path and I cannot predict where the
> user will try to upload a file from.

That's not exactly the problem, but the mere fact you think you could
solve your problem that way says a lot about your misunderstanding of
the HTTP protocol.

> Isn't there a way to dynamically get
> the path from the file upload dialogue where the user browses to it and
> selects it?

What would you do with this information ? Do you really think the
server on which your application will be deployed will have any access
to the client's filesystem ???

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Regards,
Sithembewena Lloyd Dube
http://www.lloyddube.com

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