Re: How to make Django pick new urls immediately

On Fri, Oct 7, 2011 at 9:33 AM, Daniel Roseman <daniel@roseman.org.uk> wrote:

On Friday, 7 October 2011 09:20:03 UTC+1, Kayode Odeyemi wrote:

2011/10/6 Yaşar Arabacı <yasar...@gmail.com>

maybe you should restart the server? And, do you include new urls in your root url config?

OK! I just found out that if you have urls.py in different packages and these urls.py files are all included in the root package urls.py file of the app, if I have a url (say /post) defined within a python module in the package app.api, I will have to access the url like this http://example.com/api/post and not http://example/post. I was attempting the later which is the reason for the 404.

No, that's not true. The name of the app has nothing to do with it. Rather, it's the name you give when you include the app's URLs:

    (r'^randomname/', include('api.urls'))

That will include the 'api' app's URLs with the prefix 'randomname', so you would do example.com/randomname/post/.

If I understand you clearly, that means for all views in api/views.py which has its urls.py (which is within /api) included in the root package of the app like so: (r'^api/', include('api.urls')), will be accessed like this: http://example.com/api/[url-pattern]?

--
Odeyemi 'Kayode O.
http://www.sinati.com. t: @charyorde

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