Wednesday, June 24, 2015

Re: Trying to do a 'return redirect' from one view to another (python 2.7.8, django1.7)

Who sends the data_required signal? It would have to handle the return value of "send" to look for HttpResponse subclasses.

On Wed, Jun 24, 2015 at 3:42 PM, Henry Versemann <fencer1701@gmail.com> wrote:
Here's an abbreviated look at some code I have:

@receiver(data_required)
def StartProcessView(sender, **kwargs):
    #print 'StartProcessView ENTERED !...'
    try:
        request = kwargs.get('request')
        postcopy = request.POST.copy()
        print'\n StartProcessView - THE "postcopy" OBJECT HAS BEEN GOTTEN!... \n'
        #print'\n StartProcessView - PREPARING TO REDIRECT THE REQUEST TO THE "FinishGetRequestUrlsView"!... \n'
        #return redirect('canvas_app/finishgetrequests/')
        #return redirect('/canvas_app/finishgetrequests/')
        return redirect('finishgettingrequests')
    except:
        print ' "StartProcessView" - Unexpected Error: ', str(sys.exc_info()[0])
        raise
  
def FinishGetRequestUrlsView(request):
    #print 'FinishGetRequestUrlsView ENTERED !...'
    try:
        print 'FinishGetRequestUrlsView READY!...'
    except:
        print ' "FinishGetRequestUrlsView" - Unexpected Error: ', str(sys.exc_info()[0])
        raise

I want to get the redirect working before finishing the rest of the code for both views, but I have yet to get it to work at all, even once. In the current example above I'm using the name of the view I want to redirect to, to call it with and it doesn't work(I also tried doing the redirects using urls on previous attempts, but have those statements commented out here.).

So I know I'm doing something wrong, but can't quite figure out where exactly my code is wrong.

I would appreciate any help that anyone can give me.
Thanks.

Henry
  

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