Re: Views.py & template (queryset)

From the template language reference:

<https://docs.djangoproject.com/en/1.9/ref/templates/language/#accessing-method-calls>

"""

Because Django intentionally limits the amount of logic processing available in the template language, it is not possible to pass arguments to method calls accessed from within templates. Data should be calculated in views, then passed to templates for display.

"""

If you want to do something like this then you're better switching to a more complete template language, like Jinja2. But I'd also suggest you prepare your querysets entirely before passing them to templates.

Also, for Date/DateTime/Time fields you should use the lookups provided. Do this instead: .filter(dateregister__year=2016)

On Wed, Jun 1, 2016 at 11:30 AM, Franck <waschoo@gmail.com> wrote:

Hello,

First Django project... sorry ;-)

I can run that in manage.py shell, result is ok.
     Test.objects.filter(dateregister__contains='2016').count()

But how I can show this result in the template ?
{{ test.count }} works directly in the template without modify views.py, I tried with
{{ test.filter(dateregister__contains='2016').count() }}   but no result...


Models.py

from __future__ import unicode_literals
from django.db import models
from django.utils import timezone

class Test(models.Model):
    name = models.CharField(max_length=10, editable=False)
    dateregister = models.DateTimeField(auto_now=False, auto_now_add=False, null=True, blank=True, editable=False)
    def __str__(self):              # __unicode__ on Python 2
        return self.name

Views.py

from .models import Test
from datetime import datetime
from django.shortcuts import render, get_object_or_404

def test(request):
    test = Test.objects.order_by('name')
    return render(request, 'test/test.html', {'test': test})

Thanks for your help !

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