Re: Calling a function for a url tag parameter

Hey,

 

A filter would work better here if you can use one. The following should work:

 

Defined as:

@register.filter

def encode_url(link_text):

    return link_text.replace(' ', '_')

 

And in template:

{% with state_url=flow.state.description|encode_url %}

<a href="{% url 'advance-flow' flow.id state_url %}">advance</a>

{% endwith %}

 

Aubrey

 

 

On Thu, Oct 30, 2014, at 03:23 PM, Daniel Grace wrote:

Hi,

I am trying to use the url tag on some parameters, one of which needs to come from a function.

For example as follows:

{% with state_url=encode_url flow.state.description %}

<a href="{% url 'advance-flow' flow.id state_url %}">advance</a>

 

encode_url is defined as follows:

@register.simple_tag

def encode_url(link_text):

    return link_text.replace(' ', '_')

 

This causes an error on the with statement:

Request Method:GET

Request URL:http://127.0.0.1:8000/list_flows/

Django Version:1.7

Exception Type:TemplateSyntaxError

Exception Value:

'with' received an invalid token: 'flow.state.description'

 

I'm guessing that you cannot put another template tag in the "with" statement.  I cannot see a way around this.  Any ideas?

 

Thanks