Re: Working with FileFields/FieldFiles

 

 

 

On Tue, Aug 25, 2015, at 14:31, Hugo Kitano wrote:

I guess my question is more "dumb" than that.  I need a concatenated string "ab" where a is given and b is the name of a file uploaded to a field in a model.

 

Thanks!

 

Something like this?

 

    class Blah(models.Model):

        def upload_to(self, filename="untitled", instance=None):

            return "somestring" + filename

 

        data = FileField(upload_to=upload_to)

 

 

On Saturday, August 22, 2015 at 2:55:03 PM UTC-7, Hugo Osvaldo Barrera wrote:

 

 

 

On Fri, Aug 21, 2015, at 14:28, Hugo Kitano wrote:

Hi, I'm a beginner with Django, and I'm trying to figure out how to work with FieldFiles.

 

One of my models has a FileField in which the user must submit a .bed file.  I use another library in python to analyze the .bed file.

The .bed file is saved to a specific directory on disk, and I want

 

file_on_disk = Bed('/Users/.../media/statistics.bed')

 

where statistics.bed is the name of the file, and media is the directory all files are saved to.  How would I construct this line of code?

 

Thanks!

 

You're probably after the upload_to argument of FileField, which let you define where files are saved:

 

https://docs.djangoproject.com/en/1.8/ref/models/fields/#django.db.models.FileField.upload_to

 

(I assume you're already looked into MEDIA_ROOT):

 

https://docs.djangoproject.com/en/1.8/ref/settings/#media-root

 

--

Hugo Osvaldo Barrera

 

 

--

Hugo Osvaldo Barrera