RE: where is the error in pagination?

Try this one :

paginator = Paginator(queryset_list,8)  # Show 25 contacts per page
page_request_var = "page"
page = request.GET.get(page_request_var)
try:
    queryset = paginator.page(page)
except PageNotAnInteger:
    # If page is not an integer, deliver first page.
    queryset = paginator.page(1)
except EmptyPage:
    # If page is out of range (e.g. 9999), deliver last page of results.
    queryset = paginator.page(paginator.num_pages)

 

 

Sent from Mail for Windows 10

 

From: leb dev
Sent: Wednesday, September 25, 2019 2:32 PM
To: Django users
Subject: where is the error in pagination?

 

i have a django project  and it includes pagination i do not know where is the error in my code but once i tired to go to the next or previous page it crash and display the below error :

 

> can only concatenate str(not ""NoneType) to str

 

            query=request.GET.get("search")

            paginator = Paginator(queryset_list, 5) 

            page_request_var = "page"

            print("page_request_var===>",page_request_var)

            page = request.GET.get(page_request_var)

            print("page===>",page)

            queryset = paginator.get_page(page)

            print("queryset===>",queryset)

 

When i print **page** it display None

 

 

 In the browser it suppose to display **page=2&search=sam**

but instead 

it display **/?=2&20search%20=%20sam**

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