Re: Trouble getting kwargs into filter

Hi,

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Best,

Karan Sahu

On Monday, July 6, 2020, Clive Bruton <clive@indx.co.uk> wrote:

I am struggling with getting kwarg values into a queryset filter:

class UsersItemsView(ListView):
    template_name = 'testapp/user_item_list.html'

    def get_queryset(self, **kwargs):
        print('kwargs-userlist')
        print(kwargs)
        #return Item.objects.filter(user__username='clive')
        #return Item.objects.filter(user__id=2)
        return Item.objects.filter(user__id=kwargs['userlist'])

    def dispatch(self, *args, **kwargs):
        print('kwargs-userlist')
        print(kwargs['userlist'])
        return super(UsersItemsView, self).dispatch(*args, **kwargs)


On dispatch, I can see the value for "kwargs['userlist']" printed in the terminal.

But, the queryset returns an error:

    Exception Type: KeyError
    Exception Value: 'userlist'

I understand this to mean that the key 'userlist' is not in kwargs, and this is confirmed if I "print(kwargs)" inside the get_queryset

If I use the hard-coded filters, commented-out above ("user__username='clive'", "user__id=2"), I get the result (from the template) that I expect.

So, how do I get the "kwargs['userlist']" passed to the queryset?


Thanks


-- Clive

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