Hello everyone
So The possible Solution
Could be
for python:
arr = <Be your array>
for i in arr:
if i % 10 == 3:
print(i)
for java
int[] arr = new int[10]; // Suppose you have 10 element in your array if you want dynamic array use ArrayList
for(int i : arr){
if(i % 10 == 3){
System.out.println(i);
if(i % 10 == 3){
System.out.println(i);
This Solution will Only work for the positive element.
Thank You
On Thu, Feb 25, 2021 at 9:44 PM Kasper Laudrup <laudrup@stacktrace.dk> wrote:
On 25/02/2021 16.59, Nagaraju Singothu wrote:
> Write a program to find the number ends with digit 3 in a array,
>
> For example for a array input [6,83,12,54,71,44,293,43,66,13,72,42,163],
> the output should be 83, 293, 43, 13, 163 - all numbers ends with digit 3.
>
It's probably just my lack of imagination, but I have a very hard time
seeing how such an algorithm could end up as a calendar widget, but
please do enlighten us.
Kind regards,
Kasper Laudrup
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