Re: How can I pass input value to view function without forms

How are you making the request?

On Thursday, May 27, 2021, 4:20:55 PM GMT+6, Bhanu prasad Ch <bp3545486@gmail.com> wrote:

Hello Boris,

      I was thinking of passing number from the input to view function call_me_when_ten()

index.html

...

<input type= number name = "numbered"/>

...

views.py

def call_me_when_ten(request):

    if request.post == 'POST':

          number = request.POST['numberid']

          if number == 10:

                 print('hello world')

    return render(request,'index.html')

I got this code from StackOverflow, but this isn't worked. Please, help me in solving out this problem.

On Wednesday, May 26, 2021 at 5:02:04 AM UTC+5:30 Boris Pérez wrote:

Hi!!! usually HttpResponseRedirects work with reverse
function...something like this
def myview(request):
return HttpResponseRedirect(reverse('arch-summary', args=[1945]))
where 'arch-summary' is the path name and args=[1945] the args it expects...
You need to modify also your urls.py to add tyhe name argument to your url...
Greetings

2021-05-25 0:57 GMT-04:00, Bhanu prasad Ch <bp35...@gmail.com>:
> Hello everyone,
> Please help me out in understanding how to pass the redirected view
> with some arguments like userid to connect the URLs in Django
> [image: Screenshot_2.png][image: Screenshot_3.png]
> When I am doing this way it is redirecting to the self page that is login.
> But I need the
> HttpResponseRedirect to redirect to the progress.
>
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