Re: Parsing an XML feed using ElementTree

On Tuesday, May 24, 2011 11:13:31 AM UTC+1, Lloyd Dube wrote:

Hi Everyone,

I am trying to parse an XML feed and display the text of each child node without any success. My code in the python shell is as follows:

>>>import urllib
>>>from xml.etree import ElementTree as ET

>>>content = urllib.urlopen('http://xml.matchbook.com/xmlfeed/feed?sport-id=&vendor=TEST&sport-name=&short-name=Po')
>>>xml_content = ET.parse(content)

I then check the xml_content object as follows:

>>>xml_content
<xml.etree.ElementTree.ElementTree instance at 0x01DC14B8>

And now, to iterate through its child nodes and print out the text of each node:

>>>for node in xml_content.getiterator('contest'):
...        name = node.attrib.get('text')
...        print name
...
>>>

Nothing is printed, even though the document does have 'contest' tags with text in them. If I try to count the contest tags and increment an integer (to see that the document is traversed) I get the same result - the int remains at 0.

>>> i = 0
>>> for node in xml_content.getiterator('contest'):
...     i += 1
...
>>> i
0

What am I getting wrong? Any hints would be appreciated.

--
Regards,
Sithembewena Lloyd Dube

This isn't really a Django question...

Nevertheless, the issue is probably in the line "name = node.attrib.get('text')". What this does is get the attribute of the current node that has the name 'text' - ie if your XML was like this:

    <contest text="foo"/>

However, what you probably have is this:

    <contest>foo</contest>

in which case you just want to access the `text` property directly:

    name = node.text

--

DR.

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