I want to send information to django use this:
wget -v --post-file=conf.xml http://192.168.23.73:8001/ipdb_file/
And the Python code is:
def receive(request):
"""
receive all the xml form myCONF.
"""
if request.method == 'POST':
conf_xml = request.body
result = handle_xml(conf_xml)
else:
result = "42"
html = "<html><body>It is now %s.</body></html>" % result
return HttpResponse(html)
I want to know how to get the filename in the WGET like conf.xml
Thank you.
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