I didn't quite understand have I sent the answer to Somecallitblues...
On Monday, May 4, 2015 at 1:48:30 PM UTC+3, Alex-droid AD wrote:
-- So write it once more
Forgot about Stores...
Let's look at Publisher and Book (those of Django documentation described)
Here is table beneath for example:
Publisher
Publisher-a | |||
Publisher-b | |||
Book | |||
id | |||
2 | book_1 | 1$ | Publisher-a |
7 | book_2 | 2$ | Publisher-b |
9 | book_3 | 0,5$ | Publisher-a |
14 | book_2 | 4$ | Publisher-b |
If I'll write something like
Publisher.objects.annotate(pr_max=Max('book__price'))
I'll get (as I understand):
Publisher pr_max
Publisher-a; 1$
Publisher-b; 4$
But I want to see wich book was selected by Max() function:
Publisher pr_max book_id
Publisher-a; 1$; 2
Publisher-b; 4$; 14
On Monday, May 4, 2015 at 1:48:30 PM UTC+3, Alex-droid AD wrote:
There is example in Django documentation about using Aggregate and Annotate clausesThe same rules apply to the aggregate() clause. If you wanted to know the lowest and highest price of any book that is available for sale in a store, you could use the aggregate:
Store.objects.annotate(min_price =Min('books__price'), max_price=Max('books__price'))Store.objects.aggregate(min_price =Min('books__price'), max_price=Max('books__price'))By this string of code I'll get min/max price each of book in each storeBut I won't see name or id of book, which was selected during use of aggregation (max or min)So the question... How can I get recordsstore min/max price book ???
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