Hi Erik,
-- I tried your solution but there are some issues:
.filter(date_created=Max('a__b__date_created')) - this is throwing error saying not proper use of group function.
If I remove the above, the result isn't correct where when I go through each 'a' in the result, associated latest B.text isn't always 'ABCD' - if there are multiple instances of B associated with an instance of A and one of the instances of B has text='ABCD' (might not be the latest date_created), that instance of B is also there in the query result.
Thanks.
On Tuesday, August 30, 2016 at 3:59:20 PM UTC+5:30, Erik Cederstrand wrote:
On Tuesday, August 30, 2016 at 3:59:20 PM UTC+5:30, Erik Cederstrand wrote:
> Den 30. aug. 2016 kl. 11.20 skrev Erik Cederstrand <erik+...@cederstrand.dk>:
>
> I'm not even sure that's possible to express in SQL, but it would probably be quite convoluted if it is. Here's an easier-to-understand solution:
>
> res = set()
> for b in B.objects.all().select_related('a').annotate(Max(' date_created')):
> if b.date_created != b.date_created__max:
> continue
> if b.text != 'ABCD':
> continue
> res.add(a)
I did some more experimenting. I think this actually does what you want:
res = [
b.a for b in B.objects
.filter(date_created=Max('a__b__date_created'))
.annotate(Max('a__b__date_created'))
.filter(text='ABCD')
.select_related('a')
]
which you can rewrite as:
A.objects.filter(
b__in=B.objects
.filter(date_created=Max('a__b__date_created'))
.annotate(Max('a__b__date_created'))
.filter(text='ABCD')
)
Erik
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