RE: Link to urls containing slug

Assuming I'm understanding your question correctly, all you need to do is reference get_absolute_url in your template.

Something like so:

 

<a href="{{ job_application.get_absolute_url }}">{{ job_application }}</a>

 

From: 'dtdave' via Django users [mailto:django-users@googlegroups.com]
Sent: Tuesday, January 31, 2017 8:46 AM
To: Django users
Subject: Link to urls containing slug

 

Within my model I have the following that links through to a detail page.

def get_absolute_url(self):

        

        kwargs = {

                  'job_id': self.job_id,

                  'slug': self.slug,

                       }

        return reverse('job_detail', kwargs=kwargs)

 

Everything works fine with this.

 

Within my urls.py I have the following:

url(r'^$', views.JobListView.as_view(), name='job_list'),

url(r'^(?P<job_id>[-\w]*)/(?P<slug>[-\w]*)/$', views.JobDetail.as_view(), name='job_detail'),

url(r'^(?P<job_id>[-\w]*)/(?P<slug>[-\w]*)/job_application/$', views.job_application, name='job_application'),

 

Then within my views.py the following:

def job_application(request, job_id, slug):

    # Retrieve job by id

    job = get_object_or_404(Job, job_id=job_id)

    """Other code here""""

 

However, I am having problems linking to this from my template in my detail page.

What structure should I be using to link to the job application from the job detail page?

 

I can access the url by going to 

http://localhost:8000/jobs/1/name-of-job/job_application/

 

Any advice would be appreciated

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