Monday, June 25, 2018

Re: Is it possible to construct reversible url names in urls.py using , regex etc

Thank you so much for your help, Melvyn.
With your help I managed to the the code running :)
Here it is, if somebody should find it helpful.

cheers, Mikkel

From somewhere, e.g. models.py
# The list of model names (just add your model names to it)
def GetItemNames():
   
return [ 'Year', 'Vintage', 'Region', 'Location' ]

# The generator of paths
def GetItemPaths():
    paths
= [ ]
   
for i in GetItemNames():
        m
= apps.get_model('items', i)
        paths
.append(path( 'list/'+i+'/' ,         ItemListView.as_view(model=m),      name=i+'_list'   ) )
        paths
.append(path( 'create/'+i+'/',        ItemCreateView.as_view(model=m),    name=i+'_create' ) )
        paths
.append(path( 'update/'+i+'/<pk>/',   ItemUpdateView.as_view(model=m),    name=i+'_update' ) )
        paths
.append(path( 'delete/'+i+'/<pk>/',   ItemDeleteView.as_view(model=m),    name=i+'_delete' ) )

   
return paths

From urls.py:
from . models import GetItemPaths
urlpatterns
= GetItemPaths() + [
    path
('/to/some/other/views/'    otherview.asView(), name='other_name'),
]




lørdag den 23. juni 2018 kl. 15.08.04 UTC+2 skrev Melvyn Sopacua:
On zaterdag 23 juni 2018 14:30:08 CEST Mikkel Kromann wrote:

> In models.py:
> def GetItemPaths():    paths = [ ]
>     for i in [ 'Model1', 'Model2', 'Model3' ]:
>         p = path( i + '/list/', ItemListView.as_view(model=i), name=i +
> '_list' )
>         paths.append(p)
>
>     return paths
>
> However, there seems to be a problem with trying to pass the model name to
> my CBV ItemListView.
> Unless I replace the model=i with e.g. model=Model1 I get the following
> error:
>
> 'str' object has no attribute '_default_manager'
>
>
> So it certainly seems that using model=i will not pass the model name.
> Is this because the argument for model= expects not a string but an object?

Yes. You can use import_module from django.functional to pass a dotted path.
Or you can use apps.get_model() to get a model class for a app name / model
name combo.

--
Melvyn Sopacua

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