Django talk: Re: Printing model fields organized by category

Error received:

path('category/', views.CategoryListview.as_view(), name='categories'),

AttributeError: module 'catalog.views' has no attribute 'CategoryListview'

Thanks for your help I greatly appreciate it.

On Monday, August 27, 2018 at 12:16:09 PM UTC-4, Matthew Pava wrote:

Oh, yes. I do it all the time myself.

You need to change

category.model_set

to

category.model_set.all

model_set is the manager. You need to treat it like any other manager.

From: django...@googlegroups.com [mailto:django...@googlegroups.com] On Behalf Of Jay
Sent: Monday, August 27, 2018 11:05 AM
To: Django users
Subject: Re: Printing model fields organized by category

Hmm, I'm getting an error:

I've changed my urls.py to this:

from django.urls import path

from . import views

urlpatterns = [

path('', views.index, name='index'),

path('books/', views.BookListView.as_view(), name='books'),

path('book/<int:pk>', views.BookDetailView.as_view(), name='book-detail'),

path('category/', views.CategoryListView.as_view(), name='categories'),

On Monday, August 27, 2018 at 11:33:14 AM UTC-4, Matthew Pava wrote:

Okay, your URL should point to your CategoryListView. That should have category_list in its context. And the template should in the category_list template.

From: django...@googlegroups.com [mailto:django...@googlegroups.com] On Behalf Of Jay
Sent: Monday, August 27, 2018 10:28 AM
To: Django users
Subject: Re: Printing model fields organized by category

Thanks Matthew, here is my views.py file:

from django.shortcuts import render #generates HTML fiels using a template and data

#from django.http import HttpResponse

from .models import Book, Author, BookInstance, Genre, Model, ModelInstance, Category, Ownership, Manufacturer, Location #imports model classes to access data in views

from django.views import generic

# Create your views here.

#def index(request):

# return HttpResponse("Hey")

def index(request):

"""View function for home page of site."""

#Generate counts of some of the main objects

num_books = Book.objects.all().count()

num_instances = BookInstance.objects.all().count()

#Available books (status - 'a')

num_instances_available = BookInstance.objects.filter(status__exact='a').count()

#The 'all()' is implied by default.

num_authors = Author.objects.count()

#Num visits to this view, as counted in the session variable

num_visits = request.session.get('num_visits', 0)

request.session['num_visits'] = num_visits + 1

context = {

'num_books': num_books,

'num_instances': num_instances,

'num_instances_available': num_instances_available,

'num_authors': num_authors,

'num_visits': num_visits,

}

#Render the HTML template index.html with the data in the context variable

return render(request, 'index.html', context=context)

class BookListView(generic.ListView):

model = Book

class BookDetailView(generic.DetailView):

model = Book

class ModelListView(generic.ListView):

model = Model

class ModelDetailView(generic.DetailView):

model = Model

class CategoryListView(generic.ListView):

model = Category

class CategoryDetailView(generic.DetailView):

model = Category

from django.contrib.auth.mixins import LoginRequiredMixin

class LoanedBooksByUserListView(LoginRequiredMixin,generic.ListView):

"""Generic class-based view listing books on loan to current user."""

model = BookInstance

template_name ='catalog/bookinstance_list_borrowed_user.html'

paginate_by = 10

def get_queryset(self):

return BookInstance.objects.filter(borrower=self.request.user).filter(status__exact='o').order_by('due_back')

On Monday, August 27, 2018 at 11:00:57 AM UTC-4, Matthew Pava wrote:

We need to see your view code. I'm assuming now that you don't have category_list in your context variable that you submitted to the template.

From: django...@googlegroups.com [mailto:django...@googlegroups.com] On Behalf Of Jay
Sent: Monday, August 27, 2018 9:20 AM
To: Django users
Subject: Re: Printing model fields organized by category

Thanks for the suggestions, I will change the name from Model after I can get this working.

So, I've changed the code using your help to:

{% if category_list %}

{% for category in category_list %}

<li>{{ category }}</li>

<ul>

{% for model in category.model_set %}

<li>

<a href="{{ model.get_absolute_url }}"> {{ model.model_number }}..........{{ model.description }} </a>

</li>

{% endfor %}

</ul>

{% endfor %}

{% else %}

There is no equipment in the database

{% endif %}

{% endblock %}

However, this just prints "There is no equipment in the database". Am I missing something? I will try to experiment a little more.

On Monday, August 27, 2018 at 9:52:56 AM UTC-4, Matthew Pava wrote:

Hi Jay,

Firstly, I would avoid calling a model "Model." Maybe "Product" would be better? It's only because of Django's models.Model class. That will likely cause confusion in the future for you.

You'll want to work with the Category model primarily and use a reverse lookup to get to the corresponding "Model" instead of working with a model_list. The reverse lookup of category to model is model_set by default. You can change the name if you want.

{% for category in category_list %}

 {{ category }}

 <ul>

 {% for model in category.model_set %}

 <li><a href="{{ model.get_absolute_url }}">{{ model }}</a></li>

 {% endfor %}

 </ul>

{% empty %}

 There is no equipment in the database with a category.

{% endfor %}

Check out https://docs.djangoproject.com/en/2.1/topics/db/examples/many_to_one/

From: django...@googlegroups.com [mailto:django...@googlegroups.com] On Behalf Of Jay
Sent: Monday, August 27, 2018 8:02 AM
To: Django users
Subject: Printing model fields organized by category

I have a Class called "Model" that has a field called "model_numbers". I have another class called "Category" that has a field called "category". In the Model Class, I have a field called category that is a Foreign Key to the field category in the Class category.

Also, here is the html that prints the modeul_number and category fields:

What the code is printing:

CATEGORY 1:

- Field 1

- Field 2

- Field 3

CATEGORY 2:

- Field 1

- Field 2

- Field 3

What I want it to print is:

CATEGORY 1:

- Field 1

- Field 2

CATEGORY 2:

- Field 3

In this way it prints out all the model numbers under their respective category name (instead of all model numbers under every category, which is not correct as each model number only has one category).

I posted about this on stackoverflow, and received a response but I am still confused.

Thank you!

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