Re: How to retrieve the latest object added (new one) in Django models and display it in the template?

Se comments below.

Den fre 24 feb. 2023 kl 12:14 skrev Byansi Samuel <samuelbyansi87@gmail.com>:

Hey everyone, l got a problem. Am trying to retrieve a single latest object added everytime, and display it in the template.
Below is my codes but;

Help me figure it out the source of the problem in these different instances below 👇

_______________________ issue number 1_______

#Action/models.py
class ActionGame(models.Model):
        name=models.Charfield()
        published=models.DateTimeField()

#Action/views.py
from Action.models import ActionGame

def action (request):
        latest_action=ActionGame.objects.filter(published=published). latest()
Context={ 'latest_action': latest_action }
return....

But it returns *error* :
name 'published' is not defined

You haven't defined what the value of published is. If you want to get the last created one the query should be:
latest_action=ActionGame.objects.latest("published") - that would give you the last published item. Another way would be:
latest_action=ActionGame.objects.order_by("published").last()

 

____________________ issue number 2________

#Action/models.py
class ActionGame(models.Model):
        name=models.Charfield()
        published=models.DateTimeField()
        class Meta:
              get_latest_by='published'

#Action/views.py
........
latest_action=ActionGame.objects. latest()
.......

#but it returns *error* :
'ActionGame' object is not iterable

Even if I try this:
............
latest_action=ActionGame.objects. latest('published')
.......

#it returns the Same error:
'ActionGame' object is not iterable

But this second issue, the error is referred in #action.html

{% for x in latest _action %}
<p>{{ x.game_name }}</p>
{% endfor %}

So the latest_action variable that you have sent to the template is an instance of ActionGame - and not a list or anything. You can only access variables in the ActionGame class. For example:

 <p>{{ lastest_action.name }}</p>

would print out the value of the name of the ActionGame instance.

Please l need your assistance.

I'm Samuel,
Thanks

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