How to pass URL to a view

Hi,

Maybe there is a better way to achieve what I am trying - so any suggestion is welcome :)

I have a small view. It does nothing much - if the user clicks a button for being interested in something he is looking at - it adds to the table of interested things. e.g. as below :

@login_required
def add_interested_project(request, project_id):
    project = get_object_or_404(Project, pk=project_id)
    try:
        InterestedProject.objects.get(user__pk=request.user.id, project__pk=project.id)
    except InterestedProject.DoesNotExist:
        InterestedProject.objects.create(user=request.user, project=project)
    return HttpResponseRedirect("/projects/" + project_id)

Now this works fine if he is in the details page e.g. as per the url /projects/4 . It works as expected, I am able to add to the table and it redirects back to the same page.

However, since this is something which I can call from any place, it fails in the sense that it gets redirected back to the project details page. E.g. I have a listing of projects, on /projects/ , i click the interested button, it unfortunately instead of going back to /projects/ goes to /projects/<project_id>

The code in my template file which calls this :

<a class="label label-default" href="{% url "project.views.add_interested_project" p.project.id %}"><span class="glyphicon glyphicon-heart"></span> Interested </a>

The relevant urls.py hookup :
url(r'^(?P<project_id>\d+)/add_interested_project$', views.add_interested_project, name="interestedProjects"),

The solution seems apparent that I should just pass the current URL to the view so that I can do a redirect back to it - but I am not able to get an example of how to actually implement it.

Regards,

Vibhu

--
Simplicity is the ultimate sophistication. - Leonardo da Vinci
Life is really simple, but we insist on making it complicated. - Confucius

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