Re: Access to choice-value-constants from templates when using IntegerChoices

Hi Dick,

Consider declaring model field by:

https://docs.djangoproject.com/en/3.0/ref/models/fields/#field-choices-named-groups

and template settings

On Thu, Jan 30, 2020, 02:13 Bernhard Dick <bernhard@bdick.de> wrote:

Hi,

I'm having trouble with the template-side when I'm converting my code to make use of the in version 3 introduced IntegerChoices-Class and I'd like to get some tips on doing it right.

My version 2 Code looks like this:

class StateModel(models.Model):

    STATE_DRAFT = 0

    STATE_PUBLISHED = 1

    STATE_CHOICES = [

        (STATE_DRAFT, 'draft'),

        (STATE_PUBLISHED, 'published'),

    ]

    state = models.PositiveIntegerField(choices=STATE_CHOICES, default=STATE_DRAFT)

   

In the template for a ListView I want to show an edit button next to all instances that are not yet published or where the current user has administrative permissions. Currently that can by done via

{% if instance.state == instance.STATE_DRAFT or perms.appname.manage_entries %} edit {% endif %}.

Now with the use of the IntegerChoices my model looks cleaner:

class StateModel(models.Model):

    class State(models.IntegerChoices):

        DRAFT = 0, 'draft'

        PUBLISHED = 1, 'published'

    state = models.PositiveIntegerField(choices=State, default=State.DRAFT)

But then I'm not able to access the constant values for the states from my templates. Is there a preffered way to circumvent this? One idea would to simply add some methods like:

def isDraft(self):

    return self.state == State.DRAFT

but that seems a bit boilerplate to me. I think the ideal solution would be to have something like a method named isAllowedToEdit in the model, which runs all my checks (and could be used elsewhere in the python-side of the project). But here I have the problem that I can't pass the permission information when calling from the template.

  Regards

    Bernhard

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