Re: how to use **kwargs if filters contains list of values

Yes Andreas Kuhne, I ultimately went with something like this only!!
Thanks for the reply.


On Thursday, May 28, 2020 at 5:37:33 PM UTC+5:30, Andréas Kühne wrote:

Simply put - you can't..... not without if statements.

What I would do is something like this:

query = Q()

for item in kwargs.items():

  if isinstance(item[1], list):

    query &= Q(**{f"{item[0]}__in": item[1]})

  else:

    query &= Q(**{item[0]: item[1]})

query_set = query_set.filter(query)

Regards,

Andréas

Den tors 28 maj 2020 kl 12:45 skrev Manvi Tyagi <manvit...@gmail.com>:

i have a dict of filters , 

something like

{

    "name": "string",

    "status": [

      "A", "B"

    ],

    "reg": "string",

    "oc": [

      "As","jb"

    ]

  }

```query_set = query_set.filter(**filters)``` This works fine for all the filters whose type is not list , How do apply the filters on list values?
PS: I know about __in know I can do something like 

  # if status_list:

        #     query_set = query_set.filter(status__in=status_list)

BUT , 
1. I dont want to use if else statemnets
2. I want to have dynamic variables in the filters arguments and not hardcore ones like status__in

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