Rendering XML using XSLT

I have a view that opens an XML file (it happens to be a schema but that doesn't matter) that specifies a stylesheet.

It works as expected when opening the XML file locally.

​The stylesheet isn't applied when viewing the file via Django and I see in Firebug that I am getting a 404 on the stylesheet. The stylesheet is in the same directory as the XML file.

So how do I setup a view or add this file to my existing view so it is found? 

The view:

​def get_ccddetails(request, id):

    ccd = CCD.objects.get(pk=id)

    ccdid= ccd.ct_id

    CWD = os.getcwd()

    if CWD == '/':    # Live site

        frm_dir = "/home/ccdgen/ccdlib/CCD_"+ ccdid

    else:             # development

        frm_dir = "ccdlib/CCD_"+ ccdid

    filename = frm_dir+"/ccd-"+ccdid+".xsd"

    if os.path.isfile(filename):

        response = HttpResponse(mimetype="application/xml; charset=utf-8")

        f = open(filename, encoding="utf-8")

        for line in f:

            response.write(line)

        f.close()

    else:

        response = HttpResponseNotFound("<h1>XSD: "+filename+" was not found.</h1>")

    return response

​The URL:

​    url(r'^get_xsd/(?P<id>\d+)$', "ccdgen.views.get_ccddetails", name='getxsd'),

​Thanks,

Tim​

 

============================================
Timothy Cook
LinkedIn Profile:http://www.linkedin.com/in/timothywaynecook

MLHIM http://www.mlhim.org

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