Re: how to get the time from date-based generic views

On Sat, Feb 26, 2011 at 1:09 PM, John Yeukhon Wong
<gokoproject@gmail.com> wrote:
> Suppose we have a django page using
> django.views.generic.date_based.object_detail (or even archive_index..
> actually doesn't really matter...)
>
> In the model class I saved the datetime.datetime.now which suppose to
> include the day, month, year, and time.
>
> But I have no idea how to access the time part when i am using this
> generic views
>
> What I want is Feb 26, 2011,  01:12:04 AM
> I can get the calendar part by {{ object.pub_date}}
>
> How do I get the time part?

The answer doesn't really have anything to do with class based views
-- it's a templating issue.

Your model has a field that contains a datetime field -- a single
field, called pub_date, that contains a date component and a time
component. When you output {{ object.pub_date }}, it's outputting the
entire date-time content. If you want to only show the time component,
you have two options:

2) Call the time() method on the pub_date attribute.

{{ object.pub_date.time }}

This is possible because all datetime objects (whichs is what
object.pub_date is returning) have a built-in method called time()
that returns the time component, and Django's template engine will
traverse (and invoke) built-in methods as part of the dot-notation
syntax.

1) Use the |date filter to only print time-related components.

{{ object.pub_date|date:"P" }}

would output "1:12 AM". This is ultimately the most flexible approach,
because you can determine exactly how dates are displayed. See the
docs on the date filter [1] for other formatting options.

[1] http://docs.djangoproject.com/en/1.2/ref/templates/builtins/#date

Yours
Russ Magee %-)

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