Re: render_to_response

Just have my_fnc return a dictionary (or other object), rather than the whole rendered response:

def search(request):
..........
   answ = my_fnc(roots)
   return render_to_response("my_fnc.html", { "answ" : answ['FindWord'] } )

def my_fnc( roots ):
   FindWord=authors.objects.filter("name"__contains=roots)
   return { "FindWord" : FindWord }

(A couple of style points: 

• PEP8 recommends avoiding CamelCase in favour of under_scores
• In views.py, I lean towards naming functions that aren't views, (my_fnc in this case) with an underscore, such as _my_fnc)

)

Hope this helps,

Greg

On 3 January 2011 20:45, gintare <g.statkute@gmail.com> wrote:

How formulate correctly the code below:

[code]
#views.py

def search(request):
..........
   answ = my_fnc(roots)
   return render_to_response("my_fnc.html", { "answ" : answ } )

def  my_fnc( roots ):
   FindWord=authors.objects.filter("name"__contains=roots)
   return render_to_response("my_fnc.html", { " FindWord" :
FindWord } )

[code]

Gives error Manager isn't accessible via FindWord instances

I would like to get result of quesry in separate function.
How to return this result to initial function in view or print it to
*.html form from another function?

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Director, the Interaction Consortium
http://interaction.net.au
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skype: gregturner
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